Step-by-step explanation:
T = time in seconds
H = distance
Tground = time to return to ground
Tmax = time at maximum height
H = -16T^2 + 672T...eqn 1
projectile returns to ground at H =0,
subs for H in eqn 1...
0 = -16T^2 + 672T
solving for T we get...
16T^2 = 672T
=> Tground = 42secs
Tmax = 0.5 Tground = 21secs
9. Draw a model with 3x4 model and shade in 9 squares; say its 75%
Answer:
b
Step-by-step explanation:
creditor
because bank is giving you money
Answer:
B
Step-by-step explanation:
If we reorder the equation in a certain way then it will look like this:
y-4=1/2(x-6)
y-4=1/2x-3
y-1=1/2x
y=1/2x+1
therefore B is correct since we reduced the equation to y=1/2x+1.
It may be hard to understand but the question is basically asking which one of these answers is equal to y.
Hope this helped you and let me know if i messed up or if im correct so i can imporve from my mistakes
The ball will be fastest right before it hits the ground because of gravity.
First, let's find the value of t where the ball hits the ground.
-8t²+25 = 0
-8t² = -25
t² =

t =

Note: t has to be positive, which is why there is no positive/negative symbol.
Now, let's calculate the derivative of this function. The derivative will give us the speed of the ball for time t.
d/dx = -16t
Now, let's plug in the value of t
-16 (

}
=

=

Take the absolute value of that because speed can't be negative

That's the speed of the ball. You can convert that into decimal if you'd like.
Have an awesome day! :)