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umka21 [38]
4 years ago
14

This problem is correct??

Mathematics
1 answer:
ale4655 [162]4 years ago
6 0

yes you are correct  evreything is correct

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a projectile is thrown upward so that it's distance above the ground after T seconds is H equals -16t^2 + 672 T. After how many
Arada [10]

Step-by-step explanation:

T = time in seconds

H = distance

Tground = time to return to ground

Tmax = time at maximum height

H = -16T^2 + 672T...eqn 1

projectile returns to ground at H =0,

subs for H in eqn 1...

0 = -16T^2 + 672T

solving for T we get...

16T^2 = 672T

=> Tground = 42secs

Tmax = 0.5 Tground = 21secs

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%5Ctimes%2012" id="TexFormula1" title=" \frac{3}{4} \times 12"
pentagon [3]
9. Draw a model with 3x4 model and shade in 9 squares; say its 75%
4 0
3 years ago
Please help. You can click on the photo to see the whole thing
Andrej [43]

Answer:

b

Step-by-step explanation:

creditor

because bank is giving you money

4 0
3 years ago
Which of the following is equivalent to y-4=1/2(x-6)
Talja [164]

Answer:

B

Step-by-step explanation:

If we reorder the equation in a certain way then it will look like this:

y-4=1/2(x-6)

y-4=1/2x-3

y-1=1/2x

y=1/2x+1

therefore B is correct since we reduced the equation to y=1/2x+1.

It may be hard to understand but the question is basically asking which one of these answers is equal to y.

Hope this helped you and let me know if i messed up or if im correct so i can imporve from my mistakes

7 0
3 years ago
The function f(t)=−8(t^2)+25 models the height of a ball dropped from 25 feet in the air.
Mars2501 [29]
The ball will be fastest right before it hits the ground because of gravity.

First, let's find the value of t where the ball hits the ground.

-8t²+25 = 0

-8t² = -25

t² = \frac{25}{8}

t = \frac{5}{2\sqrt{2}}

Note: t has to be positive, which is why there is no positive/negative symbol.

Now, let's calculate the derivative of this function. The derivative will give us the speed of the ball for time t.

d/dx = -16t

Now, let's plug in the value of t

-16 ( \frac{5}{2\sqrt{2}} }

= \frac{-5(8)}{\sqrt{2}}

= -20 \sqrt{2}

Take the absolute value of that because speed can't be negative

20\sqrt{2}

That's the speed of the ball. You can convert that into decimal if you'd like.

Have an awesome day! :)
5 0
3 years ago
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