Question

I REALLY NEED HELP!

Answer 1

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \ 3700\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\dotfill &7 \end{cases} \\\\\\ A=3700e^{0.045\cdot 7}\implies A=3700e^{0.315}\implies A\approx 5069.96$

Answer 2

Answer:

C. $5,069.96

Step-by-step explanation:

You are given ...

• P = 3700
• r = 0.045
• t = 7

Put these values in the formula where the corresponding variable is, then do the arithmetic.

... A = 3700·e^(0.045·7)

... = 3700·e^0.315

... ≈ 3700·1.3702593

... ≈ 5069.9594...

The balance will be $5069.96.