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NeTakaya
3 years ago
12

I REALLY NEED HELP!

Mathematics
2 answers:
anastassius [24]3 years ago
8 0

\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3700\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\dotfill &7 \end{cases} \\\\\\ A=3700e^{0.045\cdot 7}\implies A=3700e^{0.315}\implies A\approx 5069.96

Alex17521 [72]3 years ago
8 0

Answer:

C. $5,069.96

Step-by-step explanation:

You are given ...

  • P = 3700
  • r = 0.045
  • t = 7

Put these values in the formula where the corresponding variable is, then do the arithmetic.

... A = 3700·e^(0.045·7)

... = 3700·e^0.315

... ≈ 3700·1.3702593

... ≈ 5069.9594...

The balance will be $5069.96.

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