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3 years ago

Hello i need help please for my testt!

Mathematics

1 answer:

blsea [12.9K]3 years ago

8 0

Answer:

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Step-by-step explanation:

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Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6

musickatia [10]

Answer:

$(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

$(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$

Step-by-step explanation:

In order to find the values of $(x+y)^5$ and $(x+y)^6$ , you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

$(x+y)^5$ = $\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$ = $\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$ = $x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$ .

$(x+y)^6$ = $\sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i$ = $\frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6$ = $x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$ .

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3 years ago

Shelia mows 1/6 acre in 1/4 hour. How many acres does she mow in per hour?

lbvjy [14]

Answer:

2/3 = .66

Step-by-step explanation:

1/6 * 4 = 4/6 = 2/3

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3 years ago

Rewrite 6x-3y=9 in slope intercept form.

anzhelika [568]

1) Subtract 6x from both sides. -3y= -9-6x
2) Divide both sides by -3. y= 3+2x 
2) Put it in slope-intercept form: y=mx+b. y= 2x+3 

Final answer: y=2x+3

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4 years ago

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\left[x _{2}\right] = \left[ 2+\frac{\sqrt{6}}{2}\right][x2]=[2+2√6] this is answer

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4 years ago

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B each person had to pay 8

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