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mr Goodwill [35]
3 years ago
13

Hello i need help please for my testt!

Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0

Answer:

it wont load

Step-by-step explanation:

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Help plz show all your steps
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$15.5

Step-by-step explanation:

33.50-18=15.5

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2 years ago
During the first 3 days of the week, Mike read an average of 28 pages per day. During the next 4 days, Mike averaged 42 pages pe
Anestetic [448]

Answer:

36 pages per day on average

Step-by-step explanation:

Calculate the average.

3 * 28 (The first 3 days of the week where Mike reads 28 pages per day) = 84

4 * 42 (The next 4 days where Mike reads 42 pages per day ) = 168

168 + 84 = 252



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1 year ago
Which describes the shape of the distribution of total points in Mr. Price's science class?
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A bell curve describes a random distribution where at either end is a low amount with the middle representing a higher amount of points.

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8 0
2 years ago
Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

And the product of the numbers is 6 that is xy=6

Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

(x^2+y^2)^2=25+144

(x^2+y^2)^2=169

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0
2 years ago
Read 2 more answers
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