The quantity of each type of seats sold are as follows:
- Movie and a dinner seat = 200
According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.
That is, x = 4y
Also, total seats
= (x) + (y) + (z) = 3000...….............eqn(1)
Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.
- 20x + 35y + 15z = 53000...........eqn(2)
By substituting 4y for x in equations 1 and 2; we have;
<em>5y + z = 3000</em>..…........eqn(3) and
<em>115y + 15z = 53000</em>.........eqn(4)
By solving equations 3 and 4 simultaneously; we have;
y = 200 and z = 2000
and since x = 4y
x = 800
The quantity of each type of seats sold is as follows:
- Movie and a dinner seat = 200
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brainly.com/question/12413726
A perfect cube is a natural number in the form

therefore

and also you can define it as any natural number who's third root is also a natural number for examble
![\sqrt[3]{1000} = 10](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B1000%7D%20%20%3D%2010)
so you can say that the tenth perfect cube is 1000
Answer:
I just took the test and the correct answer is -6 is not in the domain of f g
Step-by-step explanation:
9514 1404 393
Answer:
(c) y=-1/2x+12
Step-by-step explanation:
The units of the problem need to be consistent. Here, it is convenient to use feet. 6 inches is 1/2 foot, so the level will decrease 1/2 ft for each hour. It starts at +12 ft, and goes down from there:
y = -1/2x +12
Answer:
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher
Step-by-step explanation:
Data provided in the question:
sample size, n = 103
Mean temperature, μ = 98.3
°
Standard deviation, σ = 0.73
Degrees of freedom, df = n - 1 = 102
Now,
For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]
Therefore,
CI = 
Thus,
Lower limit of CI = 
or
Lower limit of CI = 
or
Lower limit of CI = 98.11
and,
Upper limit of CI = 
or
Upper limit of CI = 
or
Upper limit of CI = 98.49
Hence,
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F