2 years ago

What is 12+ 12-4 %2 Hhhhhhhhhhhhhhhhhhhhhhhhhhh

Mathematics

1 answer:

prohojiy [21]2 years ago

6 0

Can you show me a picture of the problem?

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The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 5 units

Fiesta28 [93]

u go to central too lol

6 0

1 year ago

Question 8

Ratling [72]

I believe the answer is A

6 0

2 years ago

(5n2 – 4nm - 9m²) + (7n2 + 4nm +8m²) =

Flauer [41]

Answer:

$\left(5n^2-4nm-9m^2\right)+\left(7n^2+4nm+8m^2\right)=12n^2-m^2$

Step-by-step explanation:

Given the expression

$\left(5n^2\:-\:4nm\:-\:9m^2\right)\:+\:\left(7n^2\:+\:4nm\:+8m^2\right)$

Remove parentheses: (a) = a

$=5n^2-4nm-9m^2+7n^2+4nm+8m^2$

Group like terms

$=5n^2+7n^2-4nm+4nm-9m^2+8m^2$

Add similar elements: $5n^2+7n^2=12n^2$

$=12n^2-4nm+4nm-9m^2+8m^2$

Add similar elements: $-4nm+4nm=0$

$=12n^2-9m^2+8m^2$

Add similar elements: $-9m^2+8m^2=-m^2$

$=12n^2-m^2$

Therefore, we conclude that:

$\left(5n^2-4nm-9m^2\right)+\left(7n^2+4nm+8m^2\right)=12n^2-m^2$

5 0

2 years ago

pls pls pls, I beg you to answer this question only if you know the correct answer please please please I beg you please I beg y

Sonbull [250]

Answer:

I THINK its -2 -3

Step-by-step explanation:

-2 -3

4 0

3 years ago

If θ is an angle in standard position that terminates in Quadrant IV such that cosθ = 3/5, then cosθ/2 = _____. -

Sveta_85 [38]

Answer:

$cos \frac{\theta}{2}= 0.894$ .

Step-by-step explanation:

Given:

$cos\ \theta= \frac35$

We need to find $cos \ \frac{\theta}{2}$

Solution:

$cos\ \theta= \frac35$

First we will find the value of $\theta$ .

Now taking $cos^{-1}$ on both side we get;

$\theta= cos^{-1} \ \frac{3}{5}\\\\\theta = 53.13$

Now we will find the $\frac{\theta}{2}$ .

$\frac{\theta}{2}$ = $\frac{53.13}{2} = 26.565$

Now we will find $cos \ \frac{\theta}{2}$ we get;

$cos \frac{\theta}{2}=cos\ 26.565 = 0.894$

Hence $cos \frac{\theta}{2}= 0.894$ .

4 0

3 years ago