Use this formula: A = P(1 + r/n)^nt, where A is the amount after interest (what you are solving for), P is the amount you invested originally, r is the rate at which it was invested in decimal form, n is the number of times the compounding occurs each year, t is the time in years it is invested. It would look like this: A = 500(1 + [.06/12])^12*5. Do inside the parenthesis first to get 1 + .005 = 1.005. Now raise that to the 60th power (12 times 5 is 60) to get 1.34558. Now multiply that by the 500 out front to get a total amount of $674.43
A=P(1+R)^n
A=amount in 10 years
P=original amount (200)
R=rate(o.o6)
n=number of times compunded(20)
A=200x1.06^20
=641.4270944
Therefore Rachel will have 641.42 in 10 years
First join the log4 on the left:
log4( x*(x-3) = log4(-7x+21)
Then x = -7, works: -7*(-10)=70 = -7*(-7)+21
x=-3, 18 = 42, does not work
x=3 0=0 works,
However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.
Now x=3 gives log4(0) on the left and right, which does not exist.
So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
Don’t even know sry bout that
