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Lapatulllka [165]
3 years ago
6

Three groups of students used different methods to estimate the diagonal length of a patio in feet. Their results were:

Mathematics
1 answer:
podryga [215]3 years ago
5 0
F14.33 1425,413 that’s the right number
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Jenny is eight years older then twice her cousin sues age. The sum of their ages is less then 32. What is the greatest age that
maw [93]

Answer:

The age of Sue could be 7 years

Step-by-step explanation:

Jenny is 8 years older than twice her cousin Sue's age.

The first equation will be :

J = 8 + 2S ---------(1)

The sum of their ages is less than 32.

The second equation will be :

J + S < 32  ----------------(2)

Now rearrange both equations :

8 + 2S + S < 32

3S < 32 - 8

3S < 24

S < 24/3

S < 8

S = 7

The age of Sue could be 7 years.

3 0
3 years ago
What number exceeds 23 by 4 more than twice the amount by which 15 by -3
hodyreva [135]

Answer:

The required number is 63    

Step-by-step explanation :

Let the number be x

Now As per question , the equation is written as

     x - 23 = 2 × [ 15 - ( - 3) ] + 4

Or, x - 23 = 2 × ( 18) + 4

Or , x - 23 = 36 +4

Or,  x - 23 = 40

So, x = 40 + 23

∴    x = 63

Hence the required number is 63      Answer

6 0
3 years ago
You are given a 16-bit binary integer X= (1110 0100 0111 1010)2 . Convert X to decimal if:
podryga [215]

Step-by-step explanation:

a). The decimal numbers is equal to the sum of binary numbers $(b_n)$  times their powers of   $ 2(2^n) .$

That is,

$ b_n \times 2^n + b_{n-1} 2^{n-1}+ ..... + b_02^0 $

$\therefore (1110 \ \ 0100 \ \ 0111 \ \ 1010)_2 $

=  $ (0 \times 2^0) + (1 \times 2^1) + (0 \times 2^2) + (1 \times 2^3) + (1 \times 2^4) + (1 \times 2^5) + (1 \times 2^6)  + ( 0 \times 2^7) + (0 \times 2^8) + (0 \times 2^9) + (1 \times 2^{10} ) $$  + (0 \times 2^{11}) + (0 \times 2^{12}) + (1 \times 2^{13}) + (1 \times 2^{14})+ (1 \times 2^{15})$

= 58490

b).

The left most bit of the number represents the sign of the number. If bit = 1, the number is negative else if the bit is 0, the number is positive.

All the remaining bits (i.e all the bits except the leftmost bit) represent the magnitude of the number.

  Now, X = 1110 0100 0111 1010

  left most bit = 1 => number is negative

  remaining bits Y = 110 0100 0111 1010

  converting Y to decimal => Y = 25722

c).

Check the leftmost bit(lmb) of the number

if leftmost bit is 0 => convert do the binary to decimal conversion

if leftmost bit is 1, follow the following steps

  1. Flip the bits (convert the 0's into 1's and the vice versa)

  2. convert the new number from binary to decimal.

  3. Add a negative sign / multiply by -1

 Now, X = 1110 0100 0111 1010

left most bit = 1;

flipping the bits => Y = 0001 1011 1000 0101

converting Y into decimal => Y = 7045

multiplying Y with -1 => Y = -7045

Therefore, one's complement of X to decimal is -7045

Thus, X = -25722 in decimal.

d).

Check the leftmost bit(lmb) of the number

  if leftmost bit is 0 => convert do the binary to decimal conversion

  if leftmost bit is 1, follow the following steps

  1. Flip the bits (convert the 0's into 1's and the vice versa)

  2. convert the new number from binary to decimal.

  3. Add 1 to the converted number

  4. Add a negative sign / multiply by -1

Now, X = 1110 0100 0111 1010

left most bit = 1;

flipping the bits => Y = 0001 1011 1000 0101

converting Y into decimal => Y = 7045

Adding 1 to Y => Y = 7046

multiplying Y with -1 => Y = -7046

Thus, two's complement of X to decimal is -7046

7 0
3 years ago
Suppose you like to keep a jar of change on your desk. Currently, the jar contains the following: 17 Pennies 10 Dimes 19 Nickels
kap26 [50]
The probability is 18/67
5 0
3 years ago
Read 2 more answers
What is the vertex of the parabola whose equation is y = (x + 1)^2 + 3?
dalvyx [7]
The y-value of the vertex is positive 3, as shown by the +3 on the right hand side of the equation, and the x-value is -1, from the (x+1)^2 (remember, when the number is inside the brackets, flip the sign) The vertex would be (-1, 3) 

If you are looking for a rigorous answer (calculus), we must find the mininum point of the equation: f(x) = (x+1)^2 + 3 f
f'(x) = 2(x+1) = 2x + 2
2x + 2 = 0 
x = -1
f(1) = (-1 + 1)^2 + 3
f(1) = 0 + 3 = 3
(-1, 3)
5 0
3 years ago
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