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3 years ago

BRAINLIEST AND 20 POINTS

Mathematics

2 answers:

jek_recluse [69]3 years ago

5 0

Sin x = cos (90 - x)

Its B

Mice21 [21]3 years ago

3 0

Taking a wild guess here but I think it is D...

If wrong, let me know.

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A cube has a lateral area of 9 square centimeters. What is the length of each edge of the cube?

aliya0001 [1]

The lateral area of a cube is the area of four of its sides combined. The equation for a cube's lateral area would be A=s^2*4
9=s^2*4 (plug in what we know)
9/4=s^2 (divide by 4)
s=3/2 (square root both sides)

8 0

3 years ago

Read 2 more answers

Arrange the terms of each polynomial so that the powers of X are in descending order. Please help

egoroff_w [7]

Answer:

you use the FOIL method

Step-by-step explanation:

First

Inner

Outer

Last

you just distribute the numbers to all of the others then simplify.

ex.

(x+4)^2

(x+4)(x+4)

x^2+4x+4x+16

x^2+8x+16

in this, x times x is x^2. then x times 4 is 4x and 4 times x is 4x and 4 times 4 is 16. then combine like terms

7 0

3 years ago

Which can be used to solved the expression (r^-4)^3

Oksana_A [137]

Answer:

The expression is equal to 1 over 12 factors of r

Multiplying the exponents will create an equivalent expression.

Step-by-step explanation:

We are given the following in the question:

$(r^-^4)^3$

<h3>Properties of exponent: </h3>

$(x^m)^n=x^m^n$

$x^-^a=\frac{1}{x^a}$

Thus, we can simplify the given expression as:

$(r^-^4)^3$

= $r^-^1^2$

= $\frac{1}{r^1^2}$

Thus, the correct answer is:

Option 2) The expression is equal to 1 over 12 factors of r

Option 4) Multiplying the exponents will create an equivalent expression.

3 0

3 years ago

Plzzzzzzzz! A suitcase lock has a code 4 symbols long. The symbols on the lock are a star, a square, a circle, a triangle, a lin

34kurt

Answer:

$\dfrac{1}{30}$

Step-by-step explanation:

6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:

6•5•4•3 = 360

If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.

So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:

1•1•4•3 = 12

The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

$\dfrac{1\cdot1\cdot4\cdot3}{6\cdot5\cdot4\cdot3}=\dfrac{1\cdot1}{6\cdot5}=\dfrac{1}{30}$

7 0

3 years ago

Simplify:

svetlana [45]

Answer:

−(7p+6)−2(−1−2p) = - 3p - 4

Step-by-step explanation:

−(7p+6)−2(−1−2p) = -7p - 6 + 2 + 4p

= (-7p + 4p) + (2 - 6)

= -(7p - 4p) - (6 - 2)

= - 3p - 4

7 0

2 years ago