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Allushta [10]
3 years ago
15

Plz help, so confused, will report, just need these answers and explainations, correctly, thanks:)

Mathematics
2 answers:
Bad White [126]3 years ago
6 0

Answer: 35

Step-by-step explanation:

Lera25 [3.4K]3 years ago
3 0
It is 35 good luck :)
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7. The amount of memory on a CD determines how many songs I can download to it.<br> Indep.<br> Dep.
galina1969 [7]

\bf \underset{dependent}{\stackrel{\textit{songs I can download}}{S(M)}}~~=~~\underset{independent}{\stackrel{\textit{how much memory I have}}{M}}

the memory is the independent, because that can vary at will, so it's independently varying at will, whilst the amount of songs are limited to how much memory there's in the CD, so the songs are dependent on the memory availability.

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3 years ago
The inequality | x + 2 | −10<br><br><br> A. x −10<br> B. x −12<br> C. x −16<br> D. x −8
zaharov [31]

Answer:

X-8 is the best answer there

6 0
3 years ago
Solve the simultaneous equations 8 x + 5 y = 28 4 x + 5 y = 16
Nostrana [21]

Answer:

x=3, y=0.8

Step-by-step explanation:

8x+5y=28

4x+5y=16

Subtract the second simultaneous equation from the first.

You are left with: 4x=12

12/4=3

x=3

Substitute this back into one of the equations.

8(3)+5y=28

8*3=24

28-24=4

4=5y

4/5=0.8

y=0.8

5 0
3 years ago
Read 2 more answers
Find the height of the triangle.​
lesya [120]

Answer:

72.83

Step-by-step explanation:

61²+x²=95²

3721+x²=9025

x²=<u> </u><u>530</u><u>4</u>

<u>x</u><u>=</u><u> </u><u>72.83</u>

5 0
3 years ago
For each of the following vector fields
olga nikolaevna [1]

(A)

\dfrac{\partial f}{\partial x}=-16x+2y

\implies f(x,y)=-8x^2+2xy+g(y)

\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y

\implies\dfrac{\mathrm dg}{\mathrm dy}=10y

\implies g(y)=5y^2+C

\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}

(B)

\dfrac{\partial f}{\partial x}=-8y

\implies f(x,y)=-8xy+g(y)

\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x

\implies \dfrac{\mathrm dg}{\mathrm dy}=x

But we assume g(y) is a function of y alone, so there is not potential function here.

(C)

\dfrac{\partial f}{\partial x}=-8\sin y

\implies f(x,y)=-8x\sin y+g(x,y)

\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y

\implies\dfrac{\mathrm dg}{\mathrm dy}=4y

\implies g(y)=2y^2+C

\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}

For (A) and (C), we have f(0,0)=0, which makes C=0 for both.

4 0
3 years ago
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