Which lengths could be the sides KLM of the triangle, respectively?

a surveyor measures the distance to the two landmarks as shown in the diagram what is the distance d. between the landmarks

Inessa [10]

<h3>The distance between two landmarks is 123 meters</h3>

Solution:

We have to find the distance between two landmarks

Use the law of cosines

The third side of a triangle can be found when we know two sides and the angle between them

$c^2 = a^2 + b^2 - 2ab\ cos c$

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

c = d

Therefore,

$d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123$

Thus, the distance between two landmarks is 123 meters

8 0

3 years ago

What values of c makes the polynomial a perfect square? x^2+16x+c

katovenus [111]

For
ax^2+bx+c=
and a=1

b/2 squared=c makes a perfect square

b=16
16/2=8
8^2=64

the value of c should be 64

factored form
(x+8)^2

5 0

2 years ago

I'm confused What is the answer?

forsale [732]

If c > 0, then f(x - c) is a shift of f(x) by c units to the right, and f(x + c) is a shift by c units to the left.

If d > 0, then f(x) - d is a shift by d units downward, and f(x) + d is a shift by d units upward.

Let g(x) = x. Then f(x) = g(x + a) - b = (x + a) - b. So to get g(x), we translate f(x) to the left by a units, and down by b units.

Note that we can also interpret the translation as

• a shift upward of a - b units, since

(x + a) - b = x + (a - b)

• a shift b units to the right and a units upward, since

(x + a) - b = x + (a - b) = x + (- b + a) = (x - b) + a.

6 0

2 years ago

The area of a rectangle has decreased by 2%.

MissTica

Answer:

The other side was decreased to approximately .89 times its original size, meaning it was reduced by approximately 11%

Step-by-step explanation:

We can start with the basic equation for the area of a rectangle:

l × w = a

And now express the changes described above as an equation, using "p" as the amount that the width is changed:

(l × 1.1) × (w × p) = a × .98

Now let's rearrange both of those equations to solve for a / l. Starting with the first and easiest:

w = a/l

now the second one:

1.1l × wp = 0.98a

wp = 0.98a / 1.1l

1.1 wp / 0.98 = a/l

Now with both of those equalling a/l, we can equate them:

1.1 wp / 0.98 = w

We can then divide both sides by w, eliminating it

1.1wp / 0.98w = w/w

1.1p / 0.98 = 1

And solve for p

1.1p = 0.98

p = 0.98 / 1.1

p ≈ 0.89

So the width is scaled by approximately 89%

We can double check that too. Let's multiply that by the scaled length and see if we get the two percent decrease:

.89 × 1.1 = 0.979

That should be 0.98, and we're close enough. That difference of 1/1000 is due to rounding the 0.98 / 1.1 to .89. The actual result of that fraction is 0.89090909... if we multiply that by 1.1, we get exactly .98.

6 0

2 years ago

Half a number increased by the quotient of p and t

NeX [460]

Answer:

Step-by-step explanation:

Let the number be 'x'

Half a number = $\frac{1}{2}x$

Half a number increased by the quotient of p and t

$\frac{1}{2}x+\frac{p}{t}$

6 0

2 years ago