Question

Joan is building a sandbox in the shape of a regular pentagon.The perimeter of the pentagon is 35y^4-65x^3 inches.Whaf is the length of one side of the sandbox?

Answer 1

Answer:

The length of one side of sandbox is $7y^4-13x^3$.

Step-by-step explanation:

Given:

Perimeter of Pentagon = $35y^4-65x^3$

We need to length of one side of sand box.

Solution:

Now it has been given that sand box is in the shape of regular pentagon.

The length of all side of regular pentagon are equal.

Let the length of side of the sandbox be 's'.

Now we know that;

Perimeter of regular pentagon is equal to five times its side length.

so equation can be framed as;

$5s=35y^4-65x^3$

Now taking 5 common on the right side we get;

$5s = 5(7y^4-13x^3)$

Dividing both side by 5 we get;

$\frac{5s}{5} = \frac{5(7y^4-13x^3)}{5}\\\\s=7y^4-13x^3$

Hence The length of one side of sandbox is $7y^4-13x^3$.

Answer 2

Answer:

The length of one side is  7y⁴ - 13x³.

Step-by-step explanation:

The perimeter of the pentagon is

35y⁴ – 65x³

We let s as the length of one side of the sandbox. Since the sandbox is a pentagon, it's perimeter is given by  

P = 5s

5s = 35y⁴ – 65x³

Solving for s

5s = 5(7y⁴ - 13x³)

s = 7y⁴ - 13x³