PLEASE HELP! I really need to pass this test!
2 answers:
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Answer:
Company should produce 8000 phones for the maximum profit.
Step-by-step explanation:
Function representing cost to the manufacturer is,
C(x) = -21x²+ 67000x + 20006
Function that represents the revenue generated is,
R(x) = -28x² + 179000x
Function representing profit to the company,
Profit = Revenue generated - Cost price
= -28x² + 179000x - (- 21x² + 67000x + 20006)
= -28x² + 21x² + 179000x - 67000x - 20006
P(x) = -7x² + 112000x - 20006
Since this function is a quadratic function therefore, the maximum price generated will be for
From the given quadratic function, a = (-7), b = 112000 and c = -20006
Therefore, for
Or x = 8000 the profit to the company will be maximum.
That means pear company should produce 8000 phones for the maximum profit.
Answer:
The correct option is b. approximately 68% of the data falls within 1 standard deviation (+-1) of the mean
Explanation:
According to the empirical rule of normal distribution:
1. Approximately 68% of the data falls within 1 standard deviation of the mean
2. Approximately 95% of the data falls within 2 standard deviations of the mean
3. Approximately 99.7% of the data falls within 3 standard deviations of the mean.
Therefore, among the given options, only option b adheres to the empirical rule of the normal distribution. Therefore, the option b is correct
Step-by-step explanation:
From the given gummi bear, the chance that Adam is selected for any draw is 1/3 as well as the chance he is not selected at any draw is 2/3.
a). The probability of Adam getting exactly three gummi bears = P(Adam gets selected at 3 draws and not selected at the remaining 9 draws)
=
Now, the 3 draws where Adam gets selected can be any 3 out of 12 draws in = 220
Thus, probability of Adam getting three gummi bears =
= 0.21186
b). Probability that Adam will get the three gummi bears given each person will received at the most 1 gummi bear
= P(of the remaining 9 draws after assigning one gummi bear to each one, Adam gets selected at 2 draws and not selected at 7 draws) =
= 0.23411
c). Let X = Number of the gummi bears which Adam will get. Then, X = number of draws out of 12 draws Adam gets selected and X ~ B(12, 1/3). So, Adam will get gummi bears= mean of B(12, 1/3) = 12 x (1/3) = 4
d). Let Y = Number of the gummi bears that Adam will get, given each person will received at the most 1 gummi bear Then, Y = number of draws Adam gets selected in the remaining 9 draws and Y ~ B(9, 1/3). So, the expected number of bears that Adam gets given each person received at least 1 gummi bear
= 1 + mean of B(9, 1/3) = 4
e). When every one gets atleast one gummi bear, the new sample size will be 9 and so we can say that there is a reduction in variance.