The two dot plots are missing, so i have attached it.
Answer:
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Step-by-step explanation:
From the attached image, we are told to compare the means for each plot to the nearest tenth.
Mean = Σx/n
Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;
(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133
Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles
Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143
Mean of miles run at the end of the school year = 143/14 = 10.2 miles
Thus;
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Equation is y = 4x + 5
Step-by-step explanation:
- Step 1: Find the slope of the line by m = (y2 - y1)/(x2 - x1). Here y2 = 5, y1 = 9, x1 = 1 and x2 = 0
⇒ m = (5 - 9)/(0 - 1) = 4
- Step 2: Find y-intercept, b. Since the line passes through (0, 5) b = 5
- Step 3: Write the equation in slope-intercept form
⇒ y = 4x + 5
Answer:
It’s the third ans
Step-by-step explanation:
Answer:
The answer is C
Step-by-step explanation:
Multiply all of the values by 2 and then you end up with the bigger triangle.
Mean weight of the bag of pears = u = 8 pounds
Standard deviation = s = 0.5 pounds
We have to find what percentage of bags of pears will weigh more than 8.25 pounds. This can be done using the z score.
We have to convert x = 8.25 to z scores, which will be:
z score = 0.5From the z table, the probability of z score being greater than 0.5 is 0.3085
Therefore, the probability of a bag to weigh more than 8.25 pounds is 0.3085
Thus 0.3085 or 31% (rounded to nearest integer) of bags of pears will have weight more than 8.25 pounds at the local market.
