<span>To solve this problem, we can use this formula d = rd (distance = rates x time)
She runs at a speed of 9 mph and walks at a speed of 3 mph.
Her distance running is
d = 9tr
where tr is the time she spends running
Her distance walking is
d = 3tw
where tw is the time she spends walking
The distances are the same so
9tr = 3tw
We also know that the total time is 5 hours
tr + tw = 5
tr = 5-tw
Substitute this value of tr in the first equation
9tr = 3tw
9(5-tw) = 3tw
45-9tw = 3tw
45 = 12tw
3.75= tw
Denise will spend 3.75 hours (3 hours, 45 minutes) walking back and 1.25 hours (1 hour, 15 minutes) running.</span>
First list all the factors of 12;
1, 2, 3, 4, 6, 12
now let's see which ones are multiples of 3;
3, 6, 12
so all we have left are numbers 1, 2 and 4.
hope that helps, God bless!
Answer:
11
Step-by-step explanation:
g(x) = 2x + 7
Put x as 2 and evaluate.
g(2) = 2(2) + 7
Multiply.
g(2) = 4 + 7
Add the terms.
g(2) = 11
If you think about it, the question is asking us to find the greatest common factor, or GCF, of the two numbers, 24 and 18.
First, find all of the factors of 24.
The factors are: 1, 2, 3, 4, 6, 8, 12, 24
Next, find the factors of 18.
The factors are: 1, 2, 3, 6, 9, 18
List out all of the factors that both of the numbers have.
The factors are: 1, 2, 3, 6
Whichever is the greatest of these numbers is the GCF.
The GCF is 6, so the greatest number of groups he can make and still be able to win is 6.
Hope this helps!
