Answer:
The probability that the red card came from the first stack is:
40%
Step-by-step explanation:
a) Data and Calculations:
Stack Red Blue Total
First 6 5 11
Second 9 0 9
Total 15 5 20
The probability of selecting from the first stack = 50% since equal opportunity is given to the two sacks.
The probability of red card from the first stack = 6/15 = 0.4 = 40%.
b) The probability that the red card came from the first stack is given by the number of red cards in the first stack divided by the number or red cards in the two stacks. This is equal to 6/15 = 0.4 or 40%.
Answer:
e=30
k=15/2
h=90
Step-by-step explanation:
3e=60
e=30
30+4k=60
4k=30
k=15/2
15/2+2h=30
2h=45/2
h=90
Answer:
-x+2
Step-by-step explanation:
3x+(2−4x)
=3x+2-4x
=3x-4x+2
=-x+2
I hope this helps!
Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
ΔADC ≅ ΔBCD (SAS congruency)
∠AED ≅ ∠BEC (opposite angles)
ΔAED ≅ ΔBEC (ASA congruency)
Therefore DE <span>≅ CE (corresponding sides of the two congruent triangles AED and BEC)</span>
