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Rashid [163]
3 years ago
14

- في الشكل المجاور برهن أنm<E <m<CADBD AE- ​

Mathematics
1 answer:
Anna35 [415]3 years ago
5 0

Answer:

B

Step-by-step explanation:

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15x + 2x can be written as _____.<br> x(15 + 2x)<br> (15 + 2)x<br> (15x + 2x)x
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2x+15x you can just switch the two.
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a rectangular storage container without a lid is to have a volume of 10 m3. the length of its base is twice the width. material
victus00 [196]

245.31 (dollars) is the cost (in dollars) of materials for the least expensive such container.

<h3>What is maxima and minima ? </h3>

Calculus maxima and minima are found  using the concept of derivatives. Knowing that the derivative concept gives information about the slope/slope of a function, we find the point where the slope is zero. These points are called inflection points/stationary points. These are the points associated with the maximum or minimum (local) values ​​of the function.

Knowledge of maxima and minima is essential for our everyday problems. In addition, this article also explains how to find the absolute maximum and minimum values.

Solvable maximum and minimum arithmetic problems  are discussed in this article.

<h3>Calculation</h3>

Suppose the width is x (m), length of the base is 2x (m), the base area is 2x^2 (m^2).

Since the volume is 10 (m^3), the height has to be 10/2x^2 (m) = 5/x^2.

The cost of making such container is

cost of base: 2x^2*15 = 30x^2

cost of sides: (2*2x*5/x^2 + 2*x*5/x^2)*9 = 270/x

The overall cost is hence the sum of the base and the sides: f(x) = 30x^2 + 270/x

The get the minimum,

df(x)/dx = 30*(2x - 9/x^2) = 0

so x = (9/2)^(1/3) = 1.651 (m)

f(x) = 245.31 (dollars)

learn more about maxima and minima here :

brainly.com/question/17467131

#SPJ4

8 0
1 year ago
How to find the minimum value of an expression
AURORKA [14]
Your answer is positive
8 0
3 years ago
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Find CE in the length indicated
nikdorinn [45]

Okay, to find length CE, your going to know the value of x. Length BC + CE = BD + DE.3x+47+x+26=27+x+10Simplify the equation to get4x+73=37+xyou can choose one of four ways to continue, but I will choose to subtract x3x+73=37Subtract 73 from both sides of the equal sign3x=-36divide by 3 on both sides of the equal sign to get the value of xx=-12Now, plug in -12 for x in length CE to get -12+26=14


5 0
3 years ago
A ball is thrown vertically upward from the top of a building 160 feet tall with an initial velocity of 48 feet per second. The
alina1380 [7]

Answer:

# after 5 seconds, the ball strikes the ground

# The ball reaches maximum height at t = 1.5 seconds

# The max height is 196 feet

Step-by-step explanation:

The equation is:

d(t)=-16t^2+48t+160

t is the time

d(t) is the distance traveled

Initial height is 160 feet and initial velocity is 48 ft/sec

If we want to find the time it takes the ball to hit the ground, we let d(t) equal to 0 and find t. Shown below:

-16t^2+48t+160=0\\t^2-3t-10=0\\(t-5)(t+2)=0\\t=5,-2

We disregard t = -2 since time can't be negative. We take t = 5

Thus, after 5 seconds, the ball strikes the ground.

The equation is a quadratic of the form: ax^2+bx+c

Matching equations, we can say:

a = -16

b = 48

c = 160

The time when ball reaches max height is given as:

t=-\frac{b}{2a}

Substituting, we find:

t=-\frac{b}{2a}\\t=-\frac{48}{2(-16)}\\t=1.5

The ball reaches maximum height at t = 1.5 seconds

The max height can be found by putting t = 1.5 into the original equation. Shown below:

d(t)=-16t^2+48t+160\\d(1.5)=-16(1.5)^2+48(1.5)+160\\=196

The max height is 196 feet

8 0
3 years ago
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