Answer:
25*pi or
78.5 square units.
Step-by-step explanation:
If there was no shaded area, the area of the circle would be pi * r^2
r = 10
Area = pi * 10^2
Area = 100 * pi
Since there is a shaded area, the shaded part looks to be 1/4 of the whole. There's no indication of what it actually is, but 1/4 should be close enough.
Area_shade = 1/4 (100*pi)
Area_shade = 25 * pi
That's one answer.
Another is 25 * 3.14 = 78.5 square units
Answer:
Step-by-step explanation:
OS ≅ OU, so we will set those 2 expressions equal to each other and solve for y:
6y = 42 so
y = 7
Same goes for OT and OV:
x + 5 = 23 so
x = 18 and
SU = 84
Part a: subtract 48-30=18
Part b: i found it by subtracting 48 -30 because it says left over
Answer:
Option 3 - 
Step-by-step explanation:
Given : Perpendicular to the line
; containing the point (4,4).
To Find : An equation for the line with the given properties ?
Solution :
We know that,
When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.
Slope of the equation 
Converting into slope form
,
Where m is the slope.


The slope of the equation is 
The slope of the perpendicular equation is 
The required slope is 

The required equation is 
Substitute point (x,y)=(4,4)



Substitute back in equation,

Therefore, The required equation for the line is 
So, Option 3 is correct.
Check the picture below.
notice, the dashed line is the "continuation" of the graph, however, for the constraints in the piece-wise, is excluded.