We want: P(x,y) => P'(-x,-y)
Check each one:
A)
P(5,5) => P'(5,-5) Wrong
B)
P(-4,5) => P'(4,5) Wrong
C)
P(-4,-1) => P'(2,4) Wrong
D)
P(1,-5) => P'(-1,5) Correct
The answer is D.
9514 1404 393
Answer:
a) domain bounds are -1 ≤ x ≤ 1, x > 1
Step-by-step explanation:
In considering the definition of any piecewise function, the domain descriptions in the function definition must match the pieces shown in the graph.
Here, the right segment has no upper bound, so x > 1 is an appropriate description of its domain.
The left segment has the points at x=-1 and x=1 included, so the appropriate domain description for that is -1 ≤ x ≤ 1.
The one answer choice that combines these domain descriptions is ...

The ordered pair (-1, 6) is the solution to the system of equations.
Step-by-step explanation:
Given equations are;
3x+2y=9 Eqn 1
y=4x+10 Eqn 2
Putting value of y from Eqn 2 in Eqn 1

Dividing both sides by 11

Putting x=-1 in Eqn 2

Solution: (-1, 6)
The ordered pair (-1, 6) is the solution to the system of equations.
The answer would be
<em>H. 30</em>
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Sin 2x - sin x=0
Using the trigonometric identity: sin 2x=2 sinx cosx
2 sinx cosx - sinx =0
Common factor sinx
sinx ( 2 cosx -1)=0
Two options:
1) sinx=0
on the interval [0,2π), the sinx=0 for x=0 and x=<span>π=3.1416→x=3.14
2) 2 cosx - 1=0
Solving for cosx
2 cosx-1+1=0+1
2 cosx = 1
Dividing by 2 both sides of the equation:
(2 cosx)/2=1/2
cosx=1/2
cosx is positive in first and fourth quadrant:
First quadrant cosx=1/2→x=cos^(-1) (1/2)→x=</span><span>π/3=3.1416/3→x=1.05
Fourth quadrant: x=</span>2π-π/3=(6π-π)/3→x=5<span>π/3=5(3.1416)/3→x=5.24
Answer: Solutions: x=0, 1.05, 3.14, and 5.24</span>