Solution of the equation sin 2x - sin x = 0 on the interval [0 , 2π) are :
x = { 0 , 1.05 , 3.14 , 5.24 }
<h3>Further explanation</h3>
Firstly , let us learn about trigonometry in mathematics.
Suppose the ΔABC is a right triangle and ∠A is 90°.
<h3>sin ∠A = opposite / hypotenuse</h3><h3>cos ∠A = adjacent / hypotenuse</h3><h3>tan ∠A = opposite / adjacent </h3>
There are several trigonometric identities that need to be recalled, i.e.
Let us now tackle the problem!
If sin x = 0 , then for the interval [0 , 2π) → x = { 0 , 3.14 }
For 2 cos x - 1 = 0 :
2 cos x = 0 + 1
2 cos x = 1
cos x = ½
If cos x = ½ , then for the interval [0 , 2π) → x = { 1.05 , 5.24 }
If we draw a graph from the function above, it will look like the picture in the attachment.
<h2>Conclusion :</h2>
Solution of the equation sin 2x - sin x = 0 on the interval [0 , 2π) are :
x = { 0 , 1.05 , 3.14 , 5.24 }
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: College
Subject: Mathematics
Chapter: Trigonometry
Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse