1.
#include <iostream>#include <string>
using namespace std;
int main(){ string chars; // This is where we will put our @ signs and print them for(int x=0;x < 5; x++){
chars = chars + '@'; // This will concatenate an @ sign at the end of the variable cout << chars << "\n"; }}
2.
#include <iostream>#include <string>
using namespace std;
int main(){ string name; // Our variable to store the name cout << "What is your name? \n"; // Asks the user for their name cin >> name; cout << "\nWell, hello " << name << "!";}
3.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; // Asks for a number cin >> number; cout << "You entered " << number << "%!";}
4.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; cin >> number;
int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient if (check == 0) { cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even" } else { cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd" }}
5.
#include <iostream>#include <string>
using namespace std;
int main(){ float r; // Our variable cout << "Enter a radius\n"; cin >> r; if (r < 0){ cout << "Lol. No."; // If the radius is less than zero print out that message } float circumference=2*3.14*r; float area=r*r*3.14; cout << "\n\n Circumference of circle: " << circumference; cout << "\n Area of circle: " << area;}
Answer:
D. 256
Explanation:
Given
Required
Determine the maximum number of output
To get the required value, we make use of the following:
Where n is the bits of the opcode.
i.e.
Substitute 8 for n in
<em>Hence, option D answers the question</em>
802.11 is a Wi-Fi standard, not a frequency, both of those operate at 2.4 GHz. Bluetooth operates at frequencies between 2402 and 2480 MHz, or 2400 and 2483.5 MHz.
Answer:
d) consumer misbehavior
Explanation:
This is an example of consumer misbehavior. What Lena is doing is not technically piracy or illegal because HBO has created the family feature on their accounts for the account to be used by multiple people at the same time. Yet, the feature was not intended to be used by individuals that are not technically family or even under the same roof. Therefore, what Lena is doing goes against HBO's reason for this feature and sharing the account as Lena is doing is ultimately hurting HBO's streaming service.