Hey there!
If Yvonne found an article that relates to her research topic, but it doesn't cite an author, then she should definitely look up another article that relates to her topic that does cite the author. She shouldn't pretend that the article that cites no author is hers, otherwise she could possibly get her grades lowered.
Hope this helps you.
Have a great day! (:
Answer:
<em>New RAID-5 Volume
</em>
Explanation:
RAID 5 <em>is a superfluous assortment of setup of independent disks using parity disk striping. </em>
Because all the disks display data and parity evenly, no single disk is a limiting factor. In the event of a disk failure, striping will also allow users to rebuild data.
RAID 5 classes have at least three and no maximum hard disk drives (HDDs). RAID 5 is deemed among the most stable RAID setups because the parity information is distributed across all drives.
The recursive method recur executes itself from within
When the statement System.out.println(recur(32)); is executed, the string value "2101" is printed
<h3>How to determine the output of the statement?</h3>
The flow of the program is as follows:
- The method keeps updating the string variable dig with the remainder of the val variable divided by 3
- When the remainder is less than or equal to 0, the method is exited
So, when 32 is divided by 3.
The remainders are 2, 1, 0 and 1
So, the output of the statement is "2101"
Read about java methods at:
brainly.com/question/19271625
Answer:
- #include <iostream>
- using namespace std;
- int main()
- {
- // declare and initialize popcorn name array
- string popcorn_name[7] = {"plain", "butter", "caramel", "cheese", "chocolate", "turtle", "zebra"};
- // declare and initialize sales array with 7 elements
- int sales[7];
-
- // A loop to prompt user to enter sales for each popcorn
- for(int i=0; i < 7; i++){
- cout<<"Enter number of sales for " + popcorn_name[i] + " :";
- cin>>sales[i];
- }
-
- // Find maximum sales
- int max = sales[0];
- int maxIndex = 0;
- for(int j=1; j < 7; j++){
- if(max < sales[j]){
- max = sales[j];
- maxIndex = j;
- }
- }
-
- // Find minimum sales
- int min = sales[0];
- int minIndex = 0;
- for(int k=1; k < 7; k++){
- if(min > sales[k]){
- min = sales[k];
- minIndex = k;
- }
- }
-
- // Print popcorn name and sales
- for(int l=0; l < 7 ; l++){
- cout<<popcorn_name[l]<<"\n";
- cout<<"Sales: "<< sales[l]<<"\n\n";
- }
-
- // Print popcorn name with maximum and minimum sales
- cout<<"Highest selling: "<< popcorn_name[maxIndex]<<"\n";
- cout<<"Lowest selling: "<<popcorn_name[minIndex]<<"\n";
- return 0;
- }
Explanation:
Create two arrays to hold the list of popcorn name and their sales (Line 5-8). Next prompt user to input the sales for each popcorn (Line 10-14). Get the maximum sales of the popcorn (Line 17-24) and minimum sales (Line 27-34). Print the popcorn name and sales (Line 37-40) and the popcorn name with highest and lowest selling (Line 43-44).
Answer:
1. List the fields needed to gain information
2. Break down the date into smaller parts
3. identify the fields holding stored data
4.distribute the fields into tables by subject
5. identify the common fields for linking tables
Explanation:
edge 2021