Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 4x2 − 3x + 2, [0, 2] Yes, it do
es not matter if f is continuous or differentiable, every function satifies the Mean Value Theorem. Yes, f is continuous on [0, 2] and differentiable on (0, 2) since polynomials are continuous and differentiable on double-struck R. No, f is not continuous on [0, 2]. No, f is continuous on [0, 2] but not differentiable on (0, 2). There is not enough information to verify if this function satifies the Mean Value Theorem. Correct: Your answer is correct. If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not satisify the hypotheses, enter DNE). c =
where f'(c) is the derivative of the function: 8x - 3;
f(b) is the function evaluated at an x value of 2 (the second number in the interval): f(b) = 12;
f(a) is the function evaluated at an x value of 1 (the first number in the interval: f(a) = 2
Setting up:
So basically what we end up with is
8c - 3 = 5 and
8c = 8 so
c = 1
This function does in fact satisfy the requirements for the MVT: it is continuous on the interval and it is differentiable on the interval as polynomials by nature are continuous and differentiable on all values of x.
