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notsponge [240]
2 years ago
11

Name the square root of 18ab and of 3bc​

Mathematics
1 answer:
Dafna11 [192]2 years ago
8 0

Answer:

  1. 6 to th<em>e</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em> </em><em>whereas</em><em>3</em><em>bc</em><em>=</em><em> </em><em>3</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>b</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>c</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em>
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3 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

Now evaluating the integral using calculator,

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




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3 years ago
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Answer:

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3 years ago
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Answer:

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7 0
3 years ago
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