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3 years ago

Helpfjfififofof help number 6

Mathematics

2 answers:

kirza4 [7]3 years ago

8 0

I think it would be 6

Nitella [24]3 years ago

8 0

Answer:

Step-by-step explanation:

The circumference of a circle is 2*pi*radius. You can multiply 2 by pi and then divide the circumference by that number to get the radius.

2 * 3.14 = 6.28

37.7/6.28 = 6.00318471, which rounds down to 6 in.

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liq [111]

Answer:

Step-by-step explanation:

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2 years ago

Which of the following lists of ordered Pairs is a function?

sergij07 [2.7K]

Answer: B

Step-by-step explanation:

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3 years ago

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

A metalworker has a metal alloy that is 25% copper and another alloy that is 60% copper.How many kilograms of each alloy should

Neporo4naja [7]

Answer:

20kg of 25% copper alloy

30kg of 60% copper alloy

Step-by-step explanation:

There are 2 kinds of metal, first metal(A) have 25% copper while the second metal(B) has 60% copper. The metalworker want to create 50kg of metal, which means the total weight of both metals is 50kg (A+B = 50). The metalworker also want the metal made of a 46% which is 23kg(0.25A + 0.6B = 0.46*50). From these sentences, we can derive 2 equations. We can solve this with substitution.

A+B = 50

A= 50-B

Let's put the first equation into the second.

0.25A + 0.6B = 0.46 *50

0.25(50-B) + 0.6B =23

12.5 - 0.25B + 0.6B =23

0.35B=23 -12.5

B= 10.5/ 0.35= 30

Then we can solve A

A= 50-B

A= 50-30

A=20

8 0

3 years ago

Please help me find x of: x-5=11-3

Anastasy [175]

Answer:

x=0

Step-by-step explanation:

x-5=11-13

x-5=-2

+5 on both sides

x=0

5 0

3 years ago

Read 2 more answers