3/8 of a lap is 1/32 of the entire race.
x - the number of laps in the race
There were 12 laps in the race.
x - the number of laps in the race
There were 12 laps in the race.
Simplify (3^5)^2/3^-2 3^10 3^9 3^8 3^12
1 answer:
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The relationship between the sides MN, MS, and MQ in the given regular heptagon is
The area to be planted with flowers is approximately <u>923.558 m²</u>
The reason the above value is correct is as follows;
The known parameters of the garden are;
The radius of the circle that circumscribes the heptagon, r = 25 m
The area left for the children playground = ΔMSQ
Required;
The area of the garden planted with flowers
Solution:
The area of an heptagon, is;
The interior angle of an heptagon = 128.571°
The length of a side, S, is given as follows;
The area of the heptagon MNSRQPO is therefore;
By sine rule, we have
∠MSQ = 128.571 - 2*23.18 = 82.211
The area of triangle, MSQ, is given as follows;
The area of the of the garden plated with flowers, , is given as follows;
= Area of heptagon MNSRQPO - Area of triangle ΔMSQ
Therefore;
= 1,842.94 - 919.382 ≈ 923.558
The area of the of the garden plated with flowers, ≈ <u>923.558 m²</u>
Learn more about figures circumscribed by a circle here:
Answer:
see below
Step-by-step explanation:
The function is written in vertex form. It has a negative vertical scale factor, so you know ...
- the vertex is (2, -4)
- the vertical scale factor is 1/2
- the parabola opens downward
Vertex form is ...
f(x) = a(x -h)^2 +k . . . . . . . . . . vertical scale factor "a", vertex (h, k)
__
Since you know the vertex and scale factor, you can plot some points on the graph. I find it convenient to think in terms of units either side of the vertex. These are values of x that would make (x-2)^2 be 1^2, 2^2, 3^2, 4^2 and so on. The vertical scale factor of -1/2 tells you that the y-differences for these points will be -1/2, -4/2, -9/2, -16/2 from the vertex. Then we have ...
vertex: (2, -4)
1 unit either side of the vertex: (1, -4.5), (3, -4.5)
2 units either side of the vertex: (0, -6), (4, -6)
3 units either side of the vertex: (-1, -8.5), (5, -8.5)
4 units either side of the vertex: (-2, -12), (6, -12)
You can plot these points and draw a smooth curve through them. Or, you can let a graphing calculator do it. The result will be similar to that shown below.
