Answer:
x=45
Step-by-step explanation:
Q -------------R------------S
suppose this is your line,
R is the mid point
and it's given that
QR = 2x
and
RS = x+3
as R is the mid point of QS
so,
QR = RS
then,
2x = x + 3
2x - x =3
x = 3
as,
it's given that RS = x + 3
then,
RS = 3 + 3
= 6 units.
(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0
Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)
sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º
The solutions when 0≤x≤360º are: 36.87º and 306.87º.
Answer:
0.5 seconds
Step-by-step explanation:
On the ground, height is 0
-16t² + 4 = 0
16t² = 4
t² = 4/16
t² = ¼
t = ½
I would try using a table. It might work better.
