Identify the correct statements about run-time errors. Choose all that apply.

Please debug the below code in Java please.

lisabon 2012 [21]

Answer:

Check the explanation

Explanation:

//Bugs are highlighted in bold text

class Invoice

Declarations

private num invoiceNumber

private string customer

private num balanceDue

private num tax

public void setInvoiceNUMBER(num number)

Declarations

num LOW_NUM = 1000

num HIGH_NUM = 9999

if number > HIGH_NUM then

invoiceNumber = 0

else

if number < LOW_NUM then

invoiceNumber = 0

else

invoiceNumber = num

endif

return

public void setCustomer(string cust)

customer = cust

return

public void setBalanceDue(num balance)

//Bug balanceDue is Invoice class varible

//but it is assigned to balance .it gives error

balance = balanceDue

setTax()

return

private void setTax()

Declarations

//Bug TAX_RATE is declared as string

//but assigned a double value

string TAX_RATE = 0.07

tax = tax * TAX_RATE

return

public void displayInvoice()

output "Invoice #", invoiceNumber

output "Customer: ", customer

output "Due: ", balanceDue

output "Tax: ", taxDue

//Bug

//Invoice class has no variable called balance .it should be balanceDue

output "Total ", balance + taxDue

return

endClass

start

Declarations

Invoice inv1

Invoice inv2

Invoice inv3

//Warning

//it gives warning object taken but not initilaized

Invoice inv4

inv1.setInvoiceNumber(1244)

inv1.setCustomer("Brown")

inv1.setBalanceDue(1000.00)

inv1.displayInvoice()

inv2.setInvoiceNumber(77777)

inv2.setCustomer("Jenkins")

inv2.setBalanceDue(2000.00)

inv2.displayInvoice()

inv3.setInvoiceNumber(888)

inv3.setCustomer("Russell")

inv3.setBalanceDue(3000.00)

//Bug

//setTax method of Invioce doesnot take any arguments

inv3.setTax(210.00)

inv3.displayInvoice()

stop

//Here is the complete program in c++

//Run the program using Microsoft visual studio 2010 vc++

#include<iostream>

#include<iomanip>

#include<string>

using namespace std;

class Invoice

{

//class varibales

private:

int invoiceNumber;

string customer;

double balanceDue;

double tax;

//class methods

public:

void setCustomer(string cus);

void displayInvoice();

void setBalanceDue(double balance);

void setInvoiceNUMBER(int number);

void setTax();

};

void Invoice::displayInvoice()

{

cout<< setw(10)<<"Invoice #"<<setw(5)<<invoiceNumber<<endl;

cout<<setw(10)<<"Customer: "<<setw(5)<<customer<<endl;

cout<<setw(10)<<"Due: "<<setw(5)<<balanceDue<<endl;

cout<<setw(10)<<"Tax: "<<setw(5)<<tax<<endl;

//Bug

//Invoice class has no variable called balance .it should be balanceDue

cout<< "Total "<< balanceDue + tax<<endl;

}

void Invoice::setCustomer(string cust)

{

customer = cust;

}

void Invoice::setInvoiceNUMBER(int number)

{

const int LOW_NUM = 1000;

const int HIGH_NUM = 9999;

if( number > HIGH_NUM )

invoiceNumber = 0;

else

if (number < LOW_NUM )

invoiceNumber = 0;

else

invoiceNumber = number;

}

void Invoice::setBalanceDue(double balance)

{

balanceDue = balance;

}

void Invoice::setTax()

{

double TAX_RATE = 0.07;

tax = balanceDue * TAX_RATE;

}

int main()

{

Invoice inv1;

Invoice inv2;

Invoice inv3;

inv1.setInvoiceNUMBER(1244);

inv1.setCustomer("Brown");

inv1.setBalanceDue(1000.00);

inv1.setTax();

inv1.displayInvoice();

inv2.setInvoiceNUMBER(77777);

inv2.setCustomer("Jenkins");

inv2.setBalanceDue(2000.00);

inv2.setTax();

inv2.displayInvoice();

inv3.setInvoiceNUMBER(888);

inv3.setCustomer("Russell");

inv3.setBalanceDue(3000.00);

inv3.setTax();

inv3.displayInvoice();

system("pause");

return 0;

}

Kindly check the output image below.

5 0

3 years ago

____________________deals with syntax and semantics ofinformation exchange.

Goshia [24]

Answer:

The answer is (a).Presentation Layer

Explanation:

This layer is located at the 6th level of the OSI model, responsible for delivering and formatting the information to the upper layer for further processing. This service is needed because different types of computer uses different data representation. The presentation layer handles issues related to data presentation and transport, including encryption,translation and compression.

3 0

3 years ago

Type (dog, cat, budgie, lizard, horse, etc.) Create a class that keeps track of the attributes above for pet records at the anim

Alenkinab [10]

Answer:

If you did the exercise with two Dog objects, it was a bit boring, right? After all, we have nothing to separate the dogs from each other and no way of knowing, without looking at the source code, which dog produced which bark.

In the previous article, I mentioned that when you create objects, you call a special method called a constructor. The constructor looks like the class name written as a method. For example, for a Dog class, the constructor would be called Dog().

The special thing about constructors is that they are the path to any new object, so they are a great place to call code that initializes an object with default values. Further, the return value from a constructor method is always an object of the class itself, which is why we can assign the return value of the constructor to a variable of the type of class we create.

However, so far, we have not actually created a constructor at all, so how come we can still call that method?

In many languages, C# included, the language gives you a free and empty constructor without you having to do anything. It is implied that you want a constructor; otherwise there would be no way of using the class for anything, so the languages just assume that you have written one.

This invisible and free constructor is called the default constructor, and, in our example, it will look like this:

public Dog(){ }

Notice that this syntax is very similar to the Speak() method we created earlier, except that we do not explicitly return a value nor do we even declare the return type of the method. As I mentioned earlier, a constructor always returns an instance of the class to which it belongs.

In this case, that is the class Dog, and that is why when we write Dog myDog = new Dog(), we can assign the new object to a variable named myDog which is of type Dog.

So let’s add the default constructor to our Dog class. You can either copy the line above or, in Visual Studio, you can use a shortcut: type ctor and hit Tab twice. It should generate the default constructor for you.

The default constructor doesn’t actually give us anything new because it is now explicitly doing what was done implicitly before. However, it is a method, so we can now add content inside the brackets that will execute whenever we call this constructor. And because the constructor runs as the very first thing in an object’s construction, it is a perfect place to add initialization code.

For example, we could set the Name property of our objects to something by adding code such as this:

public Dog()

{

this.Name = "Snoopy";

}

This example will set the Name property of any new objects to “Snoopy”.

Of course, that’s not very useful because not all dogs are called “Snoopy”, so instead, let us change the method signature of the constructor so that it accepts a parameter.

The parentheses of methods aren’t just there to look pretty; they serve to contain parameters that we can use to pass values to a method. This function applies to all methods, not just constructors, but let’s do it for a constructor first.

Change the default constructor signature to this:

public Dog(string dogName)

This addition allows us to send a string parameter into the constructor, and that when we do, we can refer to that parameter by the name dogName.

Then, add the following line to the method block:

this.Name = dogName;

This line sets this object’s property Name to the parameter we sent into the constructor.

Note that when you change the constructor’s signature, you get a case of the red squigglies in your Program.cs file.When we add our own explicit constructors, C# and .NET will not implicitly create a default constructor for us. In our Program.cs file, we are still creating the Dog objects using the default parameter-less constructor, which now no longer exists.

To fix this problem, we need to add a parameter to our constructor call in Program.cs. We can, for example, update our object construction line as such:

Dog myDog = new Dog(“Snoopy”);

Doing so will remove the red squigglies and allow you to run the code again. If you leave or set your breakpoint after the last code line, you can look at the Locals panel and verify that your object’s Name property has indeed been? Got it?

5 0

3 years ago

What happens when your project is rendered?

jok3333 [9.3K]

Answer:

B

Explanation:

when your rendering video project your computer is processing all the data that goes into creating images you experience video rendering every time you look at your computer the images on your screen has all been rendered to produce the website photo or video you are looking at

4 0

3 years ago

Int [] val = { 3, 10, 44 };

irina1246 [14]

Answer:

5) 3 0 0

Explanation:

Given data

int [] val = { 3, 10, 44 };

The total number of parameters of given array are 3, so total length of array is also 3.

The indexing of array starts with '0', Therefore the indexes of array with length zero are: {0,1,2}

The value of array at index 0 is = 3

similarly

value at index 1 = 10

value at index 2 = 44

Here, Int i = 1 is storing the value '1' in integer variable i.

In addition to that, any value of index 'i' of an array is selected using array[i].

Therefore,

val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '1' of the array because i = 1.

So value at index 1 would be = val[1] = 0

The term i++ is incrementing the value of i, it makes i =2

val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '2' of the array because i = 2 now.

So value at index 2 would be = val[2] = 0

Hence, the output would be {3 0 0}. So 5th option is correct.

4 0

3 years ago