Answer:
Median might be the answer or maybe the height?
To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b
The dimension of the 4 rectangles are:
a. length: 4x and width: 4
b. length: 11 and width: x
c. length: 2 and width: 8x
d. length: 16x and width: 1
The area of a rectangle is:

<u>Rectangle (a)</u>


<u>Rectangle (b)</u>


<u>Rectangle (c)</u>


<u>Rectangle (d)</u>


Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.
Hence, the rectangle with a different area is rectangle (b).
Read more about areas of rectangles at:
brainly.com/question/14383947
Answer:
The answer is H.
Step-by-step explanation:
There is no "b" in this y = mx + b, so it has to go through zero, eliminating the bottom two. If we insert y = 2(1), the point should be at (1, 2), and if when looking at the possible answers, we can go with letter H.
I suppose you want to know such number. Since we have a two digit number consisting of two consecutive integers, the only possible numbers are:

Since we sorted all the cases out, we simply have to check which one satisfies the requirement. For each number, we'll write four times the the sum of its digits, and add 6, hoping to get the original number.



So, the answer is 34.