What’s 100/12 as a mixed number

Heather can complete two problems in ten minutes, and when she started she had three problems done. joel can complete three prob

zzz [600]

heather can do 2 problems in 10 minutes....60 minutes in an hr
2/10 = x / 60...2 problems to 10 min = x problems to 60 min
10x = 120
x = 120/10
x = 12....so she can do 12 problems in 1 hr

Joel can complete 3 problems in 15 minutes...
3/15 = x / 60
15x = 180
x = 180/15
x = 12....so he can do 12 problems in 1 hr

so 24 problems can be done in 1 hr

Heather started with 3 problems done and Joel started with 2 problems done....added = 5 problems already done

and it is asking between 30 and 50 hrs.....so there is no equal sign in ur problem

ur answer is : 30 < 24x + 5 < 50 <==

5 0

2 years ago

HELLPPPPPPP ASAPPPP PLEASEEEE

avanturin [10]

Answer:

2. f(-7)= -3(-7)-2

21-2

=19

10. h(1)= | 1-7(1) |

|-6|

=6

11. h(-7) =|1-7(-7)|

|1-49|

|-48|

=48

12. [23-h(9) =|1-7(-9)|]

h(9) =|1-7(9)|

|-62|

23-62

=39

Step-by-step explanation:

3 0

3 years ago

Can you please help

Novosadov [1.4K]

Answer:

Fill in the answers from the first box to the second box.

Step-by-step explanation:

The picture is hard to see so I'm not 100% sure but I think you just fill in the data from the first table to the second one. For example, if the first table says 15 under morning and for whales, you type 15 in that spot on the second one. Hopefully that helped :)

8 0

2 years ago

Which of the following is not considered a credit?

klio [65]

There’s gotta be an attachment

3 0

3 years ago

Read 2 more answers

The cable between two towers of a suspension bridge can be modeled by the function shown, where x and y are measured in feet. Th

hodyreva [135]

a) x = 200 ft

b) y = 50 ft

c)

Domain: $0\leq x \leq 400$

Range: $50\leq y \leq 150$

Step-by-step explanation:

a)

The function that models the carble between the two towers is:

$y=\frac{1}{400}x^2-x+150$

where x and y are measured in feet.

Here we want to find the lowest point of the cable: this is equivalent to find the minimum of the function $y(x)$ .

In order to find the minimum of the function, we have to calculate its first derivative and require it to be zero, so:

$y'(x)=0$

The derivative of y(x) is:

$y'(x)=\frac{1}{400}\cdot 2 x^{2-1}-1=\frac{1}{200}x-1$

And requiring it to be zero,

$\frac{1}{200}x-1=0$

Solving for x,

$\frac{1}{200}x=1\\x=200 ft$

b)

In order to find how high is the road above the water, we have to find the value of y (the height of the cable) at its minimum value, because that is the point where the cable has the same height above the water as the road.

From part a), we found that the lowest position of the cable is at

$x=200 ft$

If we now substitute this value into the expression that gives the height of the cable,

$y=\frac{1}{400}x^2-x+150$

We can find the lowest height of the cable above the water:

$y=\frac{1}{400}(200)^2-200+150=50 ft$

Therefore, the height of the road above the water is 50 feet.

c)

Domain:

The domain of a function is the set of all possible values that the independent variable x can take.

In this problem, the extreme points of the domain of this function are represented by the position of the two towers.

From part a), we calculated that the lowest point of the cable is at x = 200 ft, and this point is equidistant from both towers. If we set the position of the tower on the left at

$x=0 ft$