Question

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Answer 1

Answer:

The area of the sector in circle G formed by segments $\overline{AG}$, and $\overline {GB}$ is approximately 125.66 square units

Step-by-step explanation:

The given parameters are;

The radius of the circle with center G, r = 15

The measure of the given angle, m∠AGB = 64°

The area of a sector is given as follows;

Area of a sector of a circle = (θ/360°) × π × r²

Therefore;

The area of the sector in circle G formed by segments $\overline{AG}$, and $\overline {GB}$ is given as follows;

The area of the sector in circle G  = (64°/360°) × π × 15² ≈ 125.66 square units