Question

Given that f(n) = n^2 - 4n + 3 & g(n) = 2n - 1 find gf(-2)

Answer 1

Answer:

The value of $gf\left(-2\right)$ will be:

• $gf\left(-2\right)=29$

Step-by-step explanation:

Given the functions

$f(n) = n^2 - 4n + 3$

$g\left(n\right)\:=\:2n\:-\:1$

$f\left(-2\right)\:=\:\left(-2\right)^2\:-\:4\left(-2\right)\:+\:3$

           $=\left(-2\right)^2+4\cdot \:2+3$

           $=2^2+4\cdot \:2+3$

            $=2^2+8+3$

            $=4+11$

            $=15$

so

$gf\left(-2\right)=g\left(15\right)$

             $=2n-1=2\left(15\right)-1=30-1=29$

Therefore,

• $gf\left(-2\right)=29$