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ollegr [7]
2 years ago
12

If x 2 = x + 1, find x 3 , giving your answer in the form ax + b.

Mathematics
1 answer:
GalinKa [24]2 years ago
4 0

Answer:

{x}^{2}  = x + 1 \\ x =  {x}^{2}  - 1 \\  {x}^{3}  =  { ({x}^{2}  - 1)}^{3}  \\  = (x - 1) {}^{3} (x + 1) {}^{3}

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it's c

Step-by-step explanation:

there are 8 bears and 6 monkeys!

hope this helps:)

3 0
3 years ago
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Liula [17]

Answer:

7)141

8)65

Step-by-step explanation:

8 0
2 years ago
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The m6 = (11x + 8)° and m7 = (12x – 4)° What is the measure of 4? m4 = 40° m4 = 48° m4 = 132° m4 = 140°
bezimeni [28]
M< 6 = m< 7 (vertical angles)
11x + 8 = <span>12x – 4
12x - 11x = 8 + 4
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so
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m<4 = 180 - m<6
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answer

<span>m<4 = 40</span>
7 0
3 years ago
Read 2 more answers
Laura has two large cylindrical barrels of solution in her chemical laboratory. The first barrel contains 900 liters of solution
aleksley [76]

Answer:

-36m + 900 < 44m + 100

Step-by-step explanation:

Given that:

The first barrel contains 900 liters of the solution; &

The second barrel contains 100 liters of solution.

So, Laura drains the first barrel at the rate of 36 liters/ min

Since Laura is draining the solution in the first barrel;

Then; we have - 36m + 900 litres

Also; Laura fills the second barrel at a rate of 44 liters per minute.

Since Laura is filling the barrel; we have: 44m + 100

Therefore; the inequality representing when the second barrel contains a greater or equal amount of solution than the first barrel can be expressed as:

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6 0
3 years ago
In the game of​ roulette, a player can place a ​$9 bet on the number 11, and have a 1/38 probability of winning. If the metal ba
damaskus [11]

Answer:

1. What is the expected value of the game to the​ player?

Expected value= -$0.47368

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value= -$473.68

Step-by-step explanation:

1. What is the expected value of the game to the​ player?

Expected value can tell how much you will gain/lose every time you do the game. To find the expected value you need to multiply every value with its chance to occur. There are two types of events here, winning and losing. You have 1/38 chance of winning $315 and 37/38 chance of losing $9.  

The expected value will be:

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You are expected to lose $0.47368 every time you play

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value calculated for each roll. If you want to know how much you gain/lose by multiple rolls, you just need to multiply the expected value with the number of rolls. The game has negative expected value so you are expected to lose money instead of gaining money. The money you expected to lose will be:

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You are expected to lose $473.68 if you play the game 1000 times.

6 0
2 years ago
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