A relation is given below. {(0, 0), (2, 0.5), (4, 1), (3, 1.5), (4, 2), (5, 1.5), (6, 8)} Which ordered pair can be removed to m
ake this relation a function? Why would removing this ordered pair make the relation a function? I have already learned that the one removed is (4,1) A relation is given below. {(0, 0), (2, 0.5), (4, 1), (3, 1.5), (4, 2), (5, 1.5), (6, 8)} Which ordered pair can be removed to make this relation a function? Why would removing this ordered pair make the relation a function? this not inout and out can not be the same
2 answers:
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√8 is between 2 and 3, because 2²=4<8, but 3²=9>8. Also, our value is closer to 3 than to 2, so it is more than 2.5 and we have C and D options left.
Among these two numbers we find the one which is closer to √8.
C. 27=√729 ⇒ 2.7=√7.29
D. 28=√784 ⇒ <u>2.8=√7.84</u>
Hence our answer is D) 2.8
