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sammy [17]
3 years ago
12

Si para jugar al LOTO debes elegir un cartón con 6 números, del 1 al 41, y para jugar al KINO debes elegir un cartón con 14 núme

ros, del 1 al 25. ¿En cuantos cartones supera un juego al otro considerando el total de combinaciones posibles para ambos?
Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:

En el LOTO tenes 6 números, del 1 al 41. (Cada numero se puede usar una sola vez)

Entonces tenemos 6 selecciones, y 41 opciones para la primera, 40 para la segunda (por que un numero fue usado en la primera), 39 para la tercera, etc.

El numero de combinaciones va a ser igual al producto de los números de opciones en cada caso.

CL = 41*40*39*38*37*36 = 3,237,399,360

Para el caso del KINO lo podemos afrontar de la misma forma.

El primer numero va a tener 25 opciones, el segundo 24, el tercero 23, etc.

Entonces el numero de combinaciones va a ser:

CK = 25*24*23*22*21*20*19*18*17*16*15*14*13*12 = 3.89x10^17

Ahora tomamos el cociente entre las combinaciones para cada caso, lo que va a decir cuantas veces tenemos el numero de combinaciones de LOTO en el numero de combinaciones de KINO (es decir, el numero de cartones de LOTO que necesitamos para tener las mismas combinaciones que un solo cartón de KINO)

Ck/Cl = (3.89x10^17)/3,237,399,360 = 120,031,071.8

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