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3 years ago

Let g(x) = 4x - 20 and h(x) = -1/2x + k. For what value of k is the zero of h(x) equivalent to the zero of g(x)

Mathematics

1 answer:

uranmaximum [27]3 years ago

8 0

Answer:

Step-by-step explanation:

The zero of a function is also known as the x-intercept of a function. The x-intercept of a function exists where y = 0. So we will begin by setting each of those lines = 0:

4x - 20 = 0 and -1/2x + k = 0 and then solve each for x:

4x = 20 so

x = 5 and

-1/2x = -k and

1/2x = k so

x = 2k. Now we set the 2 x expressions equal to each other and solve for k:

5 = 2k so

k = 5/2

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Choose the correct simplification of the expression (2x2y6z5)(5x4y5z3).

erastovalidia [21]

Answer:

The correct option is 4.

Step-by-step explanation:

The given expression is

$(2x^2y^6z^5)(5x^4y^5z^3)$

Simplify the given expression.

$(2x^2y^6z^5)\times (5x^4y^5z^3)$

$(2\times 5)(x^2x^4)(y^6y^5)(z^5z^3)$

$10x^{2+4}y^{6+5}z^{5+3}$ $[\because x^mx^n=x^{m+n}]$

$10x^6y^{11}z^8$

Therefore correct option is 4.

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3 years ago

What is the equation of the line?

prohojiy [21]

Answer:

A) y = -1/2x + 1/2

Step-by-step explanation:

Find the y-intercept(when x = 0), which is 1/2.

Find the slope: m = y2-y1 / x2-x1

I used points: (3, -1), (-3,2)

m = 2 - (-1) / -3 - 3

m = 3 / - 6

m = -1/2

plug this into the slope intercept form equation: y = mx + b

y = -1/2x + 1/2

7 0

3 years ago

A stunt man wants to drive a car off a ramp at an angle of 35∘ from the ground. He already has a ramp with an angle of 15∘. He p

eduard

Answer:

The second ramp needs to have 25°.

Step-by-step explanation:

Required ramp angle for driving the car from the ground = 35°.

First ramp angle = 15°

Therefore, second ramp angle equals required ramp angle minus first ramp angle, which is = 35° - 15° = 20°

The 20° ramp angle will make the total ramp angle to be equal to 35°.

That is 15° + 20° = 35°

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3 years ago

59 points on this! Pls answer

joja [24]

Answer:

(a) y = -4x + 4 (b) y = 2x + 3

<u>solving steps:</u>

note: m refers to slope and y₁ to y point and x₁ to x point

coordinates: (2,-4)

slope: -4

equation:

y - y₁ = m(x - x₁)

y - -4 = -4(x-2)

y = -4x + 8 - 4

y = - 4x + 4

coordinates: (1,5), (-1,1)

slope: $\sf \dfrac{y-y_1}{x-x_1}$

$\sf \dfrac{1-5}{-1-1}$

equation:

y - y₁ = m(x - x₁)

y - 5 = 2(x - 1)

y - 5 = 2x - 2

y = 2x - 2 + 5

y = 2x + 3

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2 years ago

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