You need 3 points to graph a quadratic function.
It is advisable that one of these points be the vertex, because the line of symmetry passes through it
Next, you need to find two other points that lie on the curve, replacing an x-value into the function and calculating the y-value. It is easier if these two points are at the same distance from the line of symmetry.
For example, if the quadratic function is y = (x - 4)² + 3, the vertex is located at (4, 3). Replacing with x = 3 into the equation, we get:
y = (3 - 4)² + 3
y = 1 + 3
y = 4
Replacing with x = 5 into the equation, we get:
y = (5 - 4)² + 3
y = 1 + 3
y = 4
Now, we need to connect the points (3, 4), (4, 3), and (5, 4) with a U shape, as follows:
Answer:
Correct option is
C
36.25
Modal class =30−40
So we have, l=30,f0=12,f1=32,f2=20 and h=10
⇒ Mode=l+2f1−f0f2f1−f0×h
=30+2×32−12−2032−12×10
=30+6.25
=36.25
∴ Mode =36.25
June is correct because <span>12 is a </span>multiple<span> of both </span>3 and 4<span>.</span>
W + L = 122
W = 3L + 14
3L + 14 + L = 122
4L + 14 = 122
4L = 122 - 14
4L = 108
L = 108/4
L = 27 <=== they lost 27 games
W = 3L + 14
W = 3(27) + 14
W = 81 + 14
W = 95 <=== they won 95 games
10.75
11.50
11.80
12.55
13.30
14.05
14.80
15.55