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pshichka [43]
3 years ago
5

What is the answer to this?

Mathematics
2 answers:
solniwko [45]3 years ago
5 0
16b^2c That’s the right answer hope this helps
Elanso [62]3 years ago
3 0
The answer is 16b^2c square root of 5c
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Someone help if your good at maths
Y_Kistochka [10]

Answer:

a) w ⇒ × 5 ⇒ -3 ⇒ z

b) x ⇒ +2 ⇒ ×7 ⇒ y

y= x+2×7= x + 14

4 0
3 years ago
What is the equation of the line that passes through the point (4,7) and has a slope of o?
Svetlanka [38]

Answer:

The equation of the line that passes through the point (4,7) and has a slope of 0 will be:

  • y=7

Step-by-step explanation:

As we know the equation of a line in a slope-intercept form of an equation is

y = mx + b

Here,

  • m is the slop
  • b is the y-intercept

so

substituting the point (4,7) and slope m=0

y = mx + b

7=0(4)+b

7=0+b

b=7

Therefore, the equation of the line that passes through the point (4,7) and has a slope of 0 will be:

y = mx + b

y=0x+7

y=7

5 0
3 years ago
P = q/4 -r solve for q
Ivan

Answer:

4(p+r) = q

Step-by-step explanation:

p = q/4 -r

Add r to each side

p+r = q/4 -r+r

p+r = q/4

Multiply each side by 4

4(p+r) = q/4*4

4(p+r) = q

4 0
3 years ago
(12x + y + z = 26
mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}26\\17\\23\end{array}\right].

Step 3:

The linear system B is represented as

\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}23\\17\\26\end{array}\right].

Step 4:

The linear system C is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}4\\11\\12\end{array}\right].

Step 5:

The linear system D is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}12\\11\\4\end{array}\right].

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

4 0
3 years ago
3 multiply by 2x - 5 = 27.
jeka94

Answer:

x=2.7

Step-by-step explanation:

27 divided by 5 = 5.4 and 5.4 divided by 2 = 2.7

8 0
4 years ago
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