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kogti [31]
3 years ago
12

Can someone tell me how this is a SyntaxError! (Python3)

Computers and Technology
1 answer:
Basile [38]3 years ago
6 0

Answer:

The expression on line 9 required 2 brackets

Explanation:

Given

The attached code

Required

Why syntax error.

The error points to line 10, but the error is actually from line 9

To get an integer input, the syntax is:

variable-name = int(input("Prompt"))

From the attached code, the line 9 is:

amount = int(input("Enter cheese order weight: ")

By comparing the syntax to the actual code on line 9, only 1 of the brackets is closed.

<em>This, in Python 3 is a sytax error</em>

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Matching parentheses. An math expression may have a number of parentheses like (, ), [, ], { and }. Each openning parenthesis (,
Solnce55 [7]
C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
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flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
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else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}


Sample Input/Output is attached

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