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miskamm [114]
3 years ago
8

Creed wanted to know if there was a correlation between number of years of education and income. He collected data and created t

he scatterplot shown:
Determine the closest correlation coefficient (r value) for this data.

Mathematics
1 answer:
Trava [24]3 years ago
5 0
Like CREED creed? cus we just talked and he denied all of this
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F(x) = -2x + 14<br> g(x) = 2x2 - 6x - 2
Alexeev081 [22]
Y-intercept (7,0) x-intercept (0,14) = f(x)= -2x+14
7 0
3 years ago
The length of time a person takes to decide which shoes to purchase is normally distributed with a mean of 8.21 minutes and a st
MaRussiya [10]

Correct answer is: P(x<6) is 0.123 and it is usual.

Solution:-

Given that the time a person takes to decide which shoes to purchase follows normal distribution. Which has mean = 8.21 minutes and standard deviation 1.90

Then probability of individual takes less than 6 minutes is

P(X<6) = P(z

           = P(z

           = 0.1230

Typically we say an event with a probability less than 5% is unusual.

But here P(X<6) = 0.123 is greater than 5% hence this is usual.

4 0
3 years ago
I need help :)<br> .....
qwelly [4]

Answer:D)

Step-by-step explanation:

5 0
3 years ago
A triangular prism container is full of water of 428 cubic cm. The water is 10 cm deep, what is the base area of the container?
Hatshy [7]
<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>

<em><u>Solution:</u></em>

<em><u>The volume of triangular prism is given as:</u></em>

v = base\ area \times height

Given that,

A triangular prism container is full of water of 428 cubic cm

The water is 10 cm deep

Therefore,

v = 428 cubic cm

h = 10 cm

<em><u>Substituting the values we get,</u></em>

428 = base\ area \times 10\\\\base\ area = \frac{428}{10}\\\\base\ area = 42.8\ cm^2

Thus the base area of triangular prism container is 42.8 cubic centimeter

3 0
4 years ago
HELP!! What is the approximate measure of angle x in the triangle shown?
Alex Ar [27]
<h3>Answer:   D)  130.5 degrees</h3>

=================================================

Work Shown:

c^2 = a^2 + b^2 - 2*a*b*\cos(C)\\\\10^2 = 5^2 + 6^2 - 2*5*6*\cos(x)\\\\100 = 25 + 36 - 60*\cos(x)\\\\100 = 61 - 60*\cos(x)\\\\100 - 61 = - 60*\cos(x)\\\\39 = - 60*\cos(x)\\\\\cos(x) = \frac{39}{-60}\\\\\cos(x) = -0.65\\\\x = \arccos(-0.65)\\\\x \approx 130.5416\\\\x \approx 130.5\\\\

Note: I used the law of cosines. Make sure your calculator is in degree mode.

6 0
3 years ago
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