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tia_tia [17]
3 years ago
5

Ln (x-2) +ln (2x-3)=2ln x

Mathematics
1 answer:
goblinko [34]3 years ago
4 0
D:x-2\ \textgreater \ 0 \wedge 2x-3\ \textgreater \ 0 \wedge x\ \textgreater \ 0\\
D:x\ \textgreater \ 2 \wedge x\ \textgreater \ \dfrac{3}{2}\wedge x\ \textgreater \ 0\\
D:x\ \textgreater \ 2\\\\
\ln (x-2) +\ln (2x-3)=2\ln x \\
\ln (x-2)(2x-3)=\ln x^2\\
(x-2)(2x-3)=x^2\\
2x^2-3x-4x+6=x^2\\
x^2-7x+6=0\\
x^2-x-6x+6=0\\
x(x-1)-6(x-1)=0\\
(x-6)(x-1)=0\\
x=6 \vee x=1\\
1\not \in D\\
\boxed{x=6}
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Determine the x-intercept and y-intercept of the following linear equations
Blizzard [7]

Answer:

Step-by-step explanation:

the x intercept takes coordinate (x,0)

the y intercept takes coordinate (0,y)

                                         x intercept                        y intercept

40: x+y=5                          (5,0)                                      (0,5)

x=0 , y=5, when y=0 x=5

41: x-y=5                            (5,0)                                      (0,-5)

x=0, -y=5 then y=-5, when y=0, x=5

42: 3x+4y=12                     (4,0)                                      (0,3)

x=0, 4y=12⇒y=12/4⇒y=3

y=0, 3x=12⇒x=12/3⇒x=4

43: 2x+3y=6                      (3,0)                                       (0,2)

x=0 , 3y=6⇒y=6/3=2

y=0 ,3y=6 ⇒ y=6/3 ⇒y=2

44: 3x+4y=-24                   (-8,0)                                      (0,-6)

x=0 , 4y=-24⇒y=-24/4 ⇒ y=-6

y=0 , 3x=-24⇒ x=-24/3⇒x=-8

45: 1/3x+2/3y=5/6            (5/2,0)                                    (0,5/4)

x=0 , 2/3 y=5/6 ⇒12y=15 ⇒ y=15/12 ⇒y=5/4

y=0 , 1/3 x=5/6 ⇒6x=15 ⇒x=15/6 ⇒x=5/2

46: x=-2                             (-2,0)                                   no y intercept

it is vertical line , there is no y intercept

47: y=15                    no x intercept                               (0,15)

horixzontal line, no x intercept

48: 3x-7y=8              (8/3,0)                                             (0,-8/7)

x=0 , -7y=8 ⇒y=-8/7

y=0 , 3x=8 ⇒x=8/3

7 0
3 years ago
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vladimir1956 [14]

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Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
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