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salantis [7]
3 years ago
6

If 7x-25 = x + 35. then the value of x is​

Mathematics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

x = 10

Step-by-step explanation:

7x-25 = x + 35

Subtract x from each side

7x-x-25 = x-x + 35

6x -25 = 35

Add 25 to each side

6x -25+25 = 35+25

6x = 60

Divide each side by 6

6x/6 = 60/6

x = 10

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300 times

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Solve for the variable x in this equation <br><br> z=6 π xy
Ksju [112]

Answer:

Step-by-step explanation:

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Explain how to solve the equation and then check the solution.<br><br> 9 = q – 4
Vika [28.1K]

Assignment: \bold{Solve \ And \ Check \ Equation: \ 9=q-4}

<><><><><><><>

Answer: \boxed{\bold{q=13}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Switch Sides

\bold{q-4=9}

[ Step Two ] Add 4 To Both Sides

\bold{q-4+4=9+4}

[ Step Three ] Simplify

\bold{q=13}

[ Step Four ] Check Your Work

\bold{13 \ - \ 4 \ = \ 9}

[ Step Five ] Question: Is Equation Correct

\bold{Equation \ Is \ Correct, \ Therefore \ q=13}

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\bold{\rightarrow Mordancy \leftarrow}

5 0
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A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer
OLEGan [10]

Answer:

The probability is  P( p <  0.9207) = 0.0012556

Step-by-step explanation:

From the question we are told

  The population proportion is p = 0.96

 The sample size is  n  =  227

 The number of graduate who had job is  k = 209

Generally given that the sample size is large enough  (i.e n >  30) then the mean of this sampling distribution is  

       \mu_x = p = 0.96

Generally the standard deviation of this sampling distribution is  

    \sigma  = \sqrt{\frac{p (1 - p )}{n} }

=>  \sigma  = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }

=>  \sigma  = 0.0130

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{k}{n}

=> \^ p =  \frac{209}{227}

=> \^ p =  0.9207

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

     P( p <  0.9207) = P( \frac{\^ p - p }{\sigma } <  \frac{0.9207 - 0.96}{0.0130 }  )

\frac{\^ p - p}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \^ p )

   P( p <  0.9207) = P(Z< -3.022 )

From the z table  the area under the normal curve to the left corresponding to    -3.022  is

     P(Z< -3.022 ) = 0.0012556

=> P( p <  0.9207) = 0.0012556

6 0
3 years ago
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