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Inessa [10]
3 years ago
10

Describe these points with a double inequality

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
7 0

Answer:

E

Step-by-step explanation:

so much words sis sossy

Bezzdna [24]3 years ago
7 0

Answer:

Step-by-step explanation:

-3$

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What is the equation of the line that is parallel to y-3x=2 and that passes through (6,1)?
Rudik [331]

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they need to have the same slope.

y - 3x = 2      Add 3x on both sides to change the equation to slope-intercept form

y - 3x + 3x = 2 + 3x

y = 3x + 2   The slope is 3, so the parallel line's slope is also 3.

Now that you know the slope, substitute/plug it into the equation

y = mx + b

y = 3x + b    To find "b", plug in the point (6, 1) into the equation, then isolate/get the variable "b" by itself

1 = 3(6) + b  

1 = 18 + b     Subtract 18 on both sides to get "b" by itself

1 - 18 = 18 - 18 + b

-17 = b

y = 3x - 17    Your answer is the 1st option

8 0
3 years ago
Read 2 more answers
. Using the Binomial Theorem explicitly, give the 15th term in the expansion of (-2x + 1)^19
timofeeve [1]
Let's rewrite the binomial as:
(1 - 2x)^{19}

\text{Binomial expansion:} (1 + x)^{n} = \sum_{r = 0}^n\left(\begin{array}{ccc}n\\r\end{array}\right) (x)^{r}

Using the binomial expansion, we get:
\text{Binomial expansion: } (1 - 2x)^{19} = \sum_{r = 0}^{19}\left(\begin{array}{ccc}19\\r\end{array}\right) (-2x)^{r}

For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.

Thus, the fifteenth term is:
\text{Binomial expansion (15th term):} \left(\begin{array}{ccc}19\\14\end{array}\right) (-2x)^{14}
3 0
3 years ago
Geometry
g100num [7]
A=27 \ cm^2 \\ \\ d_{1}=3x , \ \ d_{2} = 2x \\ \\ S=\frac{1}{2}\cdot d_{1}\cdot d_{2}\\ \\27 = \frac{1}{2}\cdot 3x \cdot 2x \\ \\ 3x^2 = 27 \ \ /:3

x^2 = 9 \\ \\3x=x=\sqrt{9}\\ \\x=3 \ cm \\ \\ d_{1}=3x = 3*3 =9 \ cm \\ \\d_{2}=2x=2*3 = 6 \ cm \\ \\ Answer : \\ The \ length \  of \ the \ diagonal  \ is:  \ d_{1}= 9 \ cm \ and \ d_{2}=  6 \ cm

7 0
4 years ago
I need help, Please Find the Volume of the figure
Mariana [72]

Answer:

Step-by-step explanation: Length x height x width

4 0
3 years ago
Find an equation of the given point and having the given slope (-5,0),m=-3
seraphim [82]

point slope form

y-y1 = m(x-x1)

y-0 = -3(x--5)

y = -3 (x+5)

in slope intercept form distribute

y =-3x-15

3 0
3 years ago
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