0.9 seconds is the correct answer
Answer:
Both plans would cost $100 if 6 gigabytes of data are used.
Explanation:
From the question, the system of equation are correctly represented by using small letter c to represent the total cost in dollars for both equations as already assumed in the question as follows:
c = 52 + 8d ........................... (1)
c = 82 + 3d ........................... (2)
Since c is common to both, equations (1) and (2) can therefore be equated and d solved for as follows:
52 + 8d = 82 + 3d
8d - 3d = 82 - 52
5d = 30
d = 30 / 5
d = 6
Substituting d = 6 into equation (1), we have:
c = 52 + (8 * 6)
c = 52 + 48
c = 100
Since d = 6 and c = 100, it therefore implies that both plans would cost $100 if 6 gigabytes of data are used.
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
Larger sample size gives less std error and hence test statistic is larger.
Step-by-step explanation:
Given that a newspaper is conducting a statewide survey concerning the race for governor. The newspaper will take a simple random sample of n registered voters and determine X = the number of voters that will vote for the Democratic candidate. Is there evidence that a clear majority of the population will vote for the Democratic candidate
Group I II
Success 640 64
Total 1200 120
p 0.533333333 0.533333333
q 0.466666667 0.466666667
se 0.014401646 0.045542003
p diff 0.033333333 0.033333333
Z 2.314550249 0.731925055
p 0.01 0.233
we find that though p is the same, std error is very small for larger sample size thus making z statistic much bigger. So we get p value less than 0.05 whereas for 120 sample size, std error is large so Z statistic is small thus making p value to accept null hypothesis
