Did you ever do this if so do you have an email I can message you on. I've been stuck on this.
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▹ Answer
<em>$49,980</em>
▹ Step-by-Step Explanation

Hope this helps!
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Answer: In particular, let’s focus our attention on the behavior of each graph at and around . 2 and x= -1 for x < 2. There are open circles at both endpoints (2, 1) and (-2, 1). The third is h (x) = 1 / (x-2)^2, in which the function curves asymptotically towards y=0 and x=2 in quadrants one and two."
Step-by-step explanation: I think this is the problem ur on
By <span>Pythagorean triple
a²+b²=c²,
c should be longest side
10²+14²=26²
100+196=676
296</span>≠676
so sides do not form Pythagorean triple, it is not a right triangle