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Lostsunrise [7]
3 years ago
9

Christopher needs to buy wooden boardes to build a box that is 12 inches long, 6 inches wide, and 8 inches high. How many square

inches of wooden boards is needed to build the box
Mathematics
1 answer:
anzhelika [568]3 years ago
4 0

Answer:

432 in²

Step-by-step explanation:

To Obtian the square inches of wooden boards required :

Area of box = 2(l * w) + 2(l * h) + 2(h * w)

Length = 12 ; width = 6 ; height = 8

Hence,

Area of box = 2(12 * 6) + 2(12 * 8) + 2(8 * 6)

Area of box = 2(72) + 2(96) + 2(48)

Area of box = 432 in²

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Can someone help thanks
MAXImum [283]

Answer:

x = 101°

y = 46°

Step-by-step explanation:

The question tells us that  ΔSTU is similar to ΔSVW. This means that the corresponding angles in each triangle are the same. We can write that like this:

∠UST = ∠WSV

∠SUT = ∠W

∠STU =  ∠V

We can then fill in the angles we know into these statements.

33° = 33°

101° = x

y = 46°

Now we know the values of x and y.

x = 101°

y = 46°


4 0
3 years ago
Read 2 more answers
A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with t
zaharov [31]

Answer:

a. 0.2

b. 0.42

c. 0.7

d. the solution is in the explanation

e. x and y are not independent

Step-by-step explanation:

a. from the joint probability mass function table,

p(x=1) and p(Y= 1)

= p(1,1) = 0.2

b. prob(0,0)+prob(0,1)+prob(1,0)+prob(1,1)

= 0.10 + 0.04 + 0.08 + 0.20

= 0.42

P(X ≤ 1 and Y ≤ 1) = 0.42

c. prob {X ≠ 0 and Y ≠ 0}

= prob(1,1) + prob(1,2) + prob(2,1) + prob(2,2)

= 0.20 + 0.06 + 0.14 + 0.30

= 0.7

d. we have to calculate the marginal pmf of x and y here.

<u>we have the x values as 0,1,</u>2

prob(x=0) = 0.1 + 0.04 + 0.02

= 0.16

prob(x=1) = 0.08 + 0.2 + 0.06

= 0.34

prob(x=2) = 0.06+0.14+0.3

= 0.50

<u>we have y values as 0,1,2</u>

prob(y=0) = .1+.08+.06

= 0.24

prob(y=1) = .04+.2+.14

= 0.38

prob(y = 2) = 0.02+0.06+0.3

= 0.38

P(X ≤ 1) = prob(x=0)+prob(x=1)

= 0.34+0.16

= 0.50

e. from the joint table we have this,

prob(1,1) = 0.2

prob(x=1) = 0.34

prob(y=1) = 0.38

then prob(x=1)*prob(y=1)

= 0.34*0.38

= 0.1292

therefore prob(1,1) is not equal to prob(x=1)*prob(y=1)

0.2≠0.1292

x and y are not independent

7 0
3 years ago
A, B and C are collinear and B is between A and C. The ratio of AB to AC is 1:3. If A is at (2,-6) and B is at (3,-1) what are t
Naddika [18.5K]

Answer:

(5, 9)

Step-by-step explanation:

The distance between A and B is 1/3 the distance between A and C.

x coordinates:

3 − 2 = 1/3 (x − 2)

1 = 1/3 (x − 2)

3 = x − 2

x = 5

y coordinates:

-1 − (-6) = 1/3 (y − (-6))

5 = 1/3 (y + 6)

15 = y + 6

y = 9

The coordinates of point C are (5, 9).

8 0
3 years ago
Read 2 more answers
Use the formula for the area of a rectangle, A = lw, where A represents the area, l represents the length, and w represents the
IgorLugansk [536]

Answer:

Area = length × breadths

5 0
3 years ago
The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean
Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 591}{42}

Z = 0.21

Z = 0.21 has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

Z = 1.515 has a pvalue of 0.9351

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{100}} = 4.2

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

Z = 2.14

Z = 2.14 has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

8 0
3 years ago
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