The temperature startedat 10 degrees F. The temperature dropped 5
1 answer:
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<h3>Answer: x = 32</h3>
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Explanation:
When we divide y over x to get a remainder of 29, this means we are dividing over a value greater than 29. This means x > 29.
If we divided over a number 29 or less, then the remainder would be smaller than the divisor.
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The variable x is some integer. When we divide y over (x/2) we get some other integer. This implies that x/2 itself is also an integer. That tells us that x is some even integer.
So far we know that x > 29 and x is some even number.
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y divided by x leads to a remainder of 29. This means
y/x = q + 29/x
for some integer q, which is the quotient.
Multiply both sides by x
x*(y/x) = x*(q + 29/x)
y = qx + 29
We'll come back to this later.
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Now divide y over (x/2) to get a remainder 13. We'll let n be the quotient this time
y/(x/2) = n + 13/(x/2)
which is equivalent to
y = n(x/2) + 13
We can multiply both sides by 2 further getting
2y = 2*( n(x/2) + 13 )
2y = nx + 26
Plug in y = qx+29 from earlier
2(qx+29) = nx + 26
2qx + 58 = nx + 26
Let's group the x terms to one side and everything else on the other side
2qx - nx = 26-58
2qx - nx = -32
-nx + 2qx = -32
nx - 2qx = 32
I multiplied both sides by -1 to turn that -32 into 32
Factoring x from the left side gives
nx - 2qx = 32
x(n - 2q) = 32
We have x as an integer, which is stated in the instructions.
In order to have x(n-2q) = 32 be true, this must mean n-2q is an integer.
We can say n-2q = 32/x, so 32/x is some integer because x is an integer.
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In short, x and n-2q are both integers. In order for the two integers to multiply to 32, the factors must be smaller than 32 or equal to 32.
So and
We don't need to worry about the second inequality since all we care about is x.
Recall that earlier we stated that x > 29 and x is even.
Combine this with and we form the compound inequality
This basically says x is a value from the set {30, 32}
But x = 30 is not a factor of 32. There's no way to have x(n-2q) = 32 be a true equation if x = 30. We must rule x = 30 out.
The only thing left is x = 32. This is the final answer.
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If x = 32 and y = 29, then we fit the requirements of the problem.
y/x = 29/32 = 0 remainder 29
y/(x/2) = 29/16 = 1 remainder 13
The solution has been confirmed.
A. Sigma notation
The formula for finding the nth value of the geometric series is given as:
an = a1 * r^n
Where,
an = nth value of the series
<span>a1 = 1st value in the geometric series = 940</span>
r = common ratio = 1/5
n = nth order
The sigma notation for the sum of this infinite geometric series is therefore,
(see attached photo)
B. Sum of the infinite geometric series
The formula for calculating the sum of an infinite geometric series is given as:
<span>S = a1 / (1 – r)</span>
Substituting the given values:
S = 940 / (1 – 1/5)
<span>S = 1,175</span>
