the value of x would be 150
Answer:
all work is pictured/shown
Answer:
Option D. (x + 4)(x + 1)
Step-by-step explanation:
From the question given above, the following data were obtained:
C = (6x + 2) L
D = (3x² + 6x + 9) L
Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:
Volume in C = ½C
Volume in C = ½(6x + 2)
Volume in C = (3x + 1) L
Volume in D = ⅓D
Volume in D = ⅓(3x² + 6x + 9)
Volume in D = (x² + 2x + 3) L
Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:
Volume in C = (3x + 1) L
Volume in D = (x² + 2x + 3) L
Total volume =?
Total volume = Volume in C + Volume in D
Total volume = (3x + 1) + (x² + 2x + 3)
= 3x + 1 + x² + 2x + 3
= x² + 5x + 4
Factorise
x² + 5x + 4
x² + x + 4x + 4
x(x + 1) + 4(x + 1)
(x + 4)(x + 1)
Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.
Answer:
Step-by-step explanation:
Let's calculate the volume of the tank per each meter in height.
The volume of a cylinder is πr²h, where h is the height.
A height of 1 meter in a tank with a radius of 5 meters would hold a volume of:
Vol = (3.14)*(5 meters)^2 *(1 meter)
Vol (m^3) = 78.54 m^3 per 1 meter height.
If the tank were filled at a rate of 3 m^3/min, it would rise at at a rate of:
(78.54 m^3/meter)/(3 m^3/min) = 0.0382 meters/minute [38.2 cm/min
