Changing the x from positive to negative, reflects the graph over the Y-Axis.
Adding 7 to X shifts the graph horizontally 7 units to the right.
The integer of 3 is negative (-3). Glad to help
I am ;-;
Doing a quiz right now- T^T
Answer:
see below
Step-by-step explanation:
a)5a−6b+7c from 13a−4b+8c
13a−4b+8c -(5a−6b+7c)
Distribute the minus sign
13a−4b+8c -5a+6b-7c
Combine like terms
8a +2b +c
b)2x²−3xy+4y² from 3x²−5xy−6y²
3x²−5xy−6y² - (2x²−3xy+4y²)
Distribute the minus sign
3x²−5xy−6y² - 2x²+3xy-4y²
Combine like terms
x²−2xy−10y²
c)x²+4xy−3y² from 2x²−5xy+y²
2x²−5xy+y² - (x²+4xy−3y²)
Distribute the minus sign
2x²−5xy+y² - x²-4xy+3y²
Combine like terms
x²−9xy+4y²
d)4x³−6x²+8x−9 from 7x³−16x+18
7x³−16x+18 - (4x³−6x²+8x−9)
Distribute the minus sign
7x³−16x+18 - 4x³+6x²-8x+9
Combine like terms
3x³+6x²−24x+27
Answer:
33
Step-by-step explanation:
Step 1: The Diagonals of the Convex Quadilateral are Mutually Perpendicular this makes the shape a Rhombus Shape
Step 2: The formula for a area of a rhombus is the multiply the two lengths and divide by two.
In this Question we have x×y÷2 or xy/2
Step 3: The sum of the lengths of the diagonals is 12
x+y=12
y=12-x
Therefore, the area, as a function of x alone = x(12-x)/2
Step 4: To find the maximum area, let's find the derivative of the area function in respect to x and then equate to 0.
d/dx(x(12-x)/2)=0
d/dx(12x - x^2) = 0
12-2x=0
12-0=2x
12=2x, divide both sides by 2
x= 6
Step 5: Calculate the Maximum Area
The maximum area will then be 6(12 - 6)/2
= (72-6)/2 = 66/2= 33
So, the maximum area is 33.
