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2 years ago

11

Enter a recursive rule for the geometric sequence?

1 answer:

Greeley [361]2 years ago

6 0

Answer:

Step-by-step explanation:

a^1=-2

a^n=a×a^n-1

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How do i simplify this problem?<br><br>12r+5s-7T+9s-4r

Nimfa-mama [501]

Answer: To simplify this problem you combine the like terms in the equation (numbers with the same variables.)

Demo: 12r + -4r = 8r

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3 years ago

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PLLZZZZ HELP WILL GIVE BRAINLIEST!

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2 years ago

During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be

rusak2 [61]

Answer:

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

$v = \frac{d}{t}$

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that $t = 2.52$ .

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that $v = 3*10^{8}$ m/s.

We have to find d. So:

$v = \frac{d}{t}$

$d = vt$

$d = 3*10^{8}*2.52$

$7.56*10^{8]$

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

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3 years ago

The width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of the

Vladimir79 [104]

The answer will be 35ft2

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2 years ago

I need the answer please. Because I think i got mine wrong

Gekata [30.6K]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

• $a^{-m}$ ⇔ $\frac{1}{a^{m} }$

• $a^{0}$ = 1

• $a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

Given

(a)

$8^{-2}$ = $\frac{1}{8^{2} }$

(b)

$\frac{1}{3^{-3} }$ = 3³

(c)

$6^{-12}$ × $6^{8}$ × $6^{0}$

= $6^{(-12+8)}$ × 1

= $6^{-4}$

= $\frac{1}{6^{4} }$

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3 years ago

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