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Gennadij [26K]
3 years ago
7

Sabrina is going to rent a bicycle while in vacation. There are two rental companies she can choose from. The first company char

ged $10 plus a rate of $2 per hour until the bicycle is returned. The second company’s rental charges can be represented by the equation c=3h+6 where c represents the rental cost and h represents the number of hours the bicycle is rented. If Sabrina plants to bicycle for 3 hours, what is the least amount she could pay in rental fees?
Mathematics
1 answer:
Mice21 [21]3 years ago
3 0

Answer:

pretty sure its 16 but im not sure.

Step-by-step explanation:

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And 588/7 =84

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3 years ago
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aleksandrvk [35]

Answer: 9 cm

Step-by-step explanation:

By multiplying 5 by 3, you get 15. this would also apply to finding the other side of the rectangle, where you multiply 3 by 3 to get 9.

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Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
easy algebra question below first correct answer gets brainliest, if you put a link i will report and block
boyakko [2]

Answer:

6x²

Step-by-step explanation:

3x×2x=6...... then an x²

Therefore answer is 6x²

3 0
2 years ago
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