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LenaWriter [7]
3 years ago
9

Marjorie needs to earn a C in her Geology class. Her current test scores are 71,77, and 72. Her final exam is worth 6 test score

s. In order to earn a C, Marjorie’s average must lie between 70 and 79 inclusive. What range of scores can Marjorie receive on the final exam to earn a C in the course?
Mathematics
1 answer:
larisa [96]3 years ago
8 0

Answer:

68 to 82 Points.

Step-by-step explanation:

To find the range of scores that Marjorie needs to have to stay in the 70 to 79 range we first need to define the variables that we need to find.

Let x = Score that Marjorie needs

Since the exam is worth 6 exams, we will then use 6x to denote the weight of the final exam.

Now we need to add all the other exams and divide it to the number of exams.

\dfrac{6x + 71 + 77 + 72}{9}

\dfrac{6x + 220}{9}

Now let's look for the score that Marjorie needs to get a 70 average.

\dfrac{6x + 220}{9}=70

We begin by multiplying both sides by 9 to remove to begin solving for x.

6x+220=(9)70

6x+220=630

6x=630-220

\dfrac{6x}{6} =\dfrac{410}{6}

x=68.33

So the minimum score that Marjorie needs is 68.

Now let's look for the score that Marjorie needs to get to a 79 average.

We still use the same values except the average.

\dfrac{6x + 220}{9}=79

We begin by multiplying both sides by 9 to remove to begin solving for x.

6x+220=(9)79

6x+220=711

6x=711-220

\dfrac{6x}{6} =\dfrac{491}{6}

x=81.83 or {tex}82[/tex]

So the range of scores that Marjorie needs to get an average of 70 to 79 is 68 to 82 Points.

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hope this answer helps you dear...take care and may u have a great day ahead!

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Use the function table to determine the slope.EXPLAIN YOUR THINKING AND HOW YOU GOT YOUR ANSWER.I WILL MARK YOU BRAINLIST!
Tom [10]

Answer:

3¼

Step-by-step explanation:

formula \frac{{y}^{2} - {y}^{1}  }{ {x}^{2} -  {x}^{1}  }

We take any of the two points shown in the question. I will take (-3, 1) and (1, 14).

x¹ = -3

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y² = 14

Now, we sub these figures into the formula.

\frac{14 - 1}{1 - ( - 3)}

This leaves us with 14-1/1+3, which we can make into 13/4

13/4 = 3¼

<em>Disclaimer</em><em>:</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>actually</em><em> </em><em>x</em><em> </em><em>(</em><em>or</em><em> </em><em>y</em><em>)</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>of</em><em> </em><em>two</em><em>,</em><em> </em><em>but</em><em> </em><em>a</em><em> </em><em>way</em><em> </em><em>to</em><em> </em><em>distinguish</em><em> </em><em>one</em><em> </em><em>x</em><em> </em><em>(</em><em>or</em><em> </em><em>y</em><em>)</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>other</em><em>.</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>label</em><em> </em><em>of</em><em> </em><em>sorts</em><em>.</em>

3 0
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The question is below​
Cloud [144]

Answer:

See below.

Step-by-step explanation:

a.

The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.

b.

Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.

c.

The formula for adding n positive integers starting at 1 is:

1 + 2 + 3 + ... + n = n(n + 1)/2

For figure 55, n = 55.

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Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.

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Answer: yes

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