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LenaWriter [7]
3 years ago
9

Marjorie needs to earn a C in her Geology class. Her current test scores are 71,77, and 72. Her final exam is worth 6 test score

s. In order to earn a C, Marjorie’s average must lie between 70 and 79 inclusive. What range of scores can Marjorie receive on the final exam to earn a C in the course?
Mathematics
1 answer:
larisa [96]3 years ago
8 0

Answer:

68 to 82 Points.

Step-by-step explanation:

To find the range of scores that Marjorie needs to have to stay in the 70 to 79 range we first need to define the variables that we need to find.

Let x = Score that Marjorie needs

Since the exam is worth 6 exams, we will then use 6x to denote the weight of the final exam.

Now we need to add all the other exams and divide it to the number of exams.

\dfrac{6x + 71 + 77 + 72}{9}

\dfrac{6x + 220}{9}

Now let's look for the score that Marjorie needs to get a 70 average.

\dfrac{6x + 220}{9}=70

We begin by multiplying both sides by 9 to remove to begin solving for x.

6x+220=(9)70

6x+220=630

6x=630-220

\dfrac{6x}{6} =\dfrac{410}{6}

x=68.33

So the minimum score that Marjorie needs is 68.

Now let's look for the score that Marjorie needs to get to a 79 average.

We still use the same values except the average.

\dfrac{6x + 220}{9}=79

We begin by multiplying both sides by 9 to remove to begin solving for x.

6x+220=(9)79

6x+220=711

6x=711-220

\dfrac{6x}{6} =\dfrac{491}{6}

x=81.83 or {tex}82[/tex]

So the range of scores that Marjorie needs to get an average of 70 to 79 is 68 to 82 Points.

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Asap answer pls-----------
marissa [1.9K]

Answer:

y=\frac{4}{5}x-\frac{18}{5}

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0).

<u>1) Determine the slope (m)</u>

m=\frac{y_2-y_1}{x_2-x_1} where two points on the line are (x_1,y_1) and (x_2,y_2)

In the graph, the points (-3,-6) and (2,-2) are plotted clearly, so we can use these to help us find the slope. Plug them into the equation:

m=\frac{-6-(-2)}{-3-2}\\m=\frac{-6+2}{-3-2}\\m=\frac{-4}{-5}\\m=\frac{4}{5}

Therefore, the slope of the line is \frac{4}{5}. Plug this into y=mx+b :

y=\frac{4}{5}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{4}{5}x+b

Typically, given a graph, we could look at where exactly the line crosses the y-axis to determine b. However, because it appears ambiguous on this graph, we must solve it algebraically.

Plug in one of the given points (2,-2) and solve for b:

-2=\frac{4}{5}(2)+b\\-2=\frac{8}{5}+b

Subtract \frac{8}{5} from both sides to isolate b

-2-\frac{8}{5}=\frac{8}{5}+b-\frac{8}{5}\\-\frac{18}{5} =b

Therefore, the y-intercept of the line is -\frac{18}{5}. Plug this back into y=\frac{4}{5}x+b:

y=\frac{4}{5}x+(-\frac{18}{5})\\y=\frac{4}{5}x-\frac{18}{5}

I hope this helps!

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