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mash [69]
3 years ago
15

Select the correct trigonometric ratios for angle 0

Mathematics
1 answer:
ratelena [41]3 years ago
3 0

Answer:

A, D, and F

Step-by-step explanation:

First off, we're not given the hypotenuse's length, so let's use the Pythagorean Theorem to find it:

1^2+3^2=c^2\\1+9=c^2\\10=c^2\\c=\sqrt{10}

With that, we can refer to SOH-CAH-TOA to help us find sine, cosine, and tangent:

SOH (Sine = Opposite/Hypotenuse)

\sin{\theta}=1/\sqrt{10}=\sqrt{10}/10

CAH (Cosine = Adjacent/Hypotenuse)

\cos{\theta}=3/\sqrt{10}=3\sqrt{10}/10

TOA (Tangent = Opposite/Adjacent)

\tan{\theta}=1/3

From this, we can see that A matches up with sine, and we can eliminate B and C.

Cosecant, secant, and cotangent are all reciprocals of the three basic trig ratios:

\csc{\theta}=1/\sin{\theta}=\sqrt{10}\\\sec{\theta}=1/\cos{\theta}=\sqrt{10}/3\\\cot{\theta}=1/\tan{\theta}=3

D matches with cosecant, and F matches with cotangent, so the correct trig rations for θ are A, D, and F.

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A construction company is building a new parking garage and is charging the following rates: $5000 a month for the first 3 month
Elena L [17]

Answer:

C(t) = 5t for 0 < t ≤ 3

C(t) = (8t-9) for 3 < t ≤ 6

C(t) = 44 for 6 < t ≤ 10

C is given in thousands of dollars and t is given in months.

Total lump sum to be paid at the end of the 6 months for the total 10 months that the construction company works on the parking garage = $44000

Step-by-step explanation:

We will do a piecewise analysis for this cost function.

How to obtain the total cost changes with each time interval.

In the first 3 months,

C(t) = 5t for 0 < t ≤ 3

Note that C is given in thousands of dollars

In the next 3 months,

C(t) = (8t-9) for 3 < t ≤ 6

- Here, it gets a little complex, we use the upper limit of the previous interval and the lower limit of this new interval to get the constant to be subtracted from the normal 8t that characterizes this interval.

8(3) = 24

5(3) = 15

constant = 24 - 15 = 9

In the last 4 months,

C(t) = 44 for 6 < t ≤ 10

- For the last four months, it is a single sum of $5000 plus the [8(6) - 9] from the previous inteval

C = [8(6) - 9] + 5 = 39 + 5 = 44

So, the cost of parking, tracked month after month gives

T | Cost (in thousands of dollars)

1 | 5

2 | 10

3 | 15

4 | 23

5 | 31

6 | 39

7 | 44

8 | 44

9 | 44

10 | 44

Total lump sum to be paid at the end of the 6 months for the total 10 months that the construction company works on the parking garage = $44000

Hope this Helps!!!

8 0
3 years ago
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