Plz help this is what might get m to a 100 so plz help me

I HAVE 10 MIN LEFT CAN SOMEONE HELP ME WITH A FEW OF THESE OR ALL OF EM?

FinnZ [79.3K]

I will help you but I need to know what you need help with , find the area or volume?

4 0

2 years ago

Please use the figure below to solve for both x and y

kkurt [141]

Answer:

x=10°

y = 12°

Step-by-step explanation:

<TSV = 5x + 4x = 90°

=> 9x = 90°

Divide by 9,

x = 10°

<RSU = 10y + 10° + 5x = 180°

=> 10y + 10° + 5*10° = 180°

=> 10y + 10° + 50° = 180°

=> 10y + 60° = 180°

Subtract 60° on both sides,

10y = 180° - 60° = 120°

Divide by 10,

y = 120° / 10 = 12°

3 0

3 years ago

Resolve into partial fractions

lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

1)

$\frac{11 + x}{(2 - x)(x - 3)} = \frac{A}{2 - x} + \frac{B}{x - 3} \\ \\ \therefore \: \frac{11 + x}{(2 - x)(x - 3)} = \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)} \\ \\ \therefore \: 11 + x = Ax - 3A + 2B - Bx \\ \\ \therefore \: 11 + x = - 3A + 2B + Ax - Bx\\ \\ \therefore \: 11 + x = - 3A + 2B + (A - B)x \\ \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\ \therefore \: A = B + 1.....(1) \\ \\ - 3A + 2B = 11....(2) \\ from \: eq \: (1) \: and \: (2) \\ - 3(B + 1) + + 2B = 11 \\ \\ - 3B - 3 + 2B = 11 \\ \\ - B = 11 + 3 \\ \\ B = - 14 \\ A = - 14 + 1 = - 13 \\ \\ \frac{11 + x}{(2 - x)(x - 3)} = \frac{ - 13}{2 - x} + \frac{ - 14}{x - 3} \\ \\ \frac{11 + x}{(2 - x)(x - 3)} = - \frac{ 13}{2 - x} - \frac{ 14}{x - 3}$